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SOVA2 [1]
2 years ago
14

In which block of the period table is chromium found

Chemistry
2 answers:
fiasKO [112]2 years ago
8 0
That should be your answer! hope this helped!

Anon25 [30]2 years ago
4 0
Chromium (Cr) is round in d block
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Carbohydrate loading Group of answer choices involves a reduction in the intensity of workouts with a corresponding increase in
SOVA2 [1]

Answer:

the correct option would be:

The group of response options implies a reduction in the intensity of the workouts with a corresponding increase in the percentage of carbohydrate intake for several days before a competition.

Since the carbohydrate load is an increase in glycogen reserves as an energy source accompanied by a decrease in muscle demand. This is often used in high-performance activities, where strict competencies are required.

Although today some professionals do not support that, but rather support a diet with carbohydrates and proteins.

Explanation:

Carbohydrate loading increases glycogen reserves, it is accompanied by a muscle rest plan, without fatigue of muscle fibers.

The purpose of this is to exhaust the muscle fibers in maximum demands such as the competencies, ensuring a necessary energy source that supplies this reaction, for which glycogen reserves are needed.

7 0
3 years ago
What kind of sport do you have interest the most and explain why? <br>​
lidiya [134]

Answer

Gymnastics

Explanation:

for the simple fact that they do cool stuff

7 0
2 years ago
Predict the splitting pattern for each of the labeled hydrogens in the following molecules. Assume that all coupling constants a
Ghella [55]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a) Splitting pattern for Ha= 2+1 , Triplet

For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3

Splitting pattern for Hb and Hc= 3+1 , Quartet

For Proton Hd, number of non equivalent protons n= 0

Splitting pattern for Hd= 0+1 , Singlet

b) Splitting pattern for Ha= 2+1 , Triplet

For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3

Splitting pattern for Hb and Hc= 3+1 , Quartet

For Proton Hd, number of non equivalent protons n= 0

Splitting pattern for Hd= 0+1 , Singlet

c) The IUPAC name is Butan-2-ol

Explanation:

Considering the first question the rule used for prediction of splitting pattern is n+1 (Pascal's Triangle rule), where n is number of H atom on the adjacent carbon which are non equivalent.

According to that for molecule 1 as shown on the second uploaded image

For Proton Ha, number of non equivalent protons n= 2

Splitting pattern for Ha= 2+1 , Triplet

For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3

Splitting pattern for Hb and Hc= 3+1 , Quartet

For Proton Hd, number of non equivalent protons n= 0

Splitting pattern for Hd= 0+1 , Singlet

Considering the second question for Molecule 2 as shown on the third uploaded image  

For Proton Ha, number of non equivalent protons n= 1

Splitting pattern for Ha= 1+1=2 , Doublet

For Proton Hb, number of non equivalent protons n= 3

Splitting pattern for Hb= 3+1=4 , Quartet

For Proton Hc, number of non equivalent protons n= 3

Splitting pattern for Hc= 3+1=4 , Quartet

For Proton Hd, number of non equivalent protons n= 1

Splitting pattern for Ha= 1+1=2 , Doublet

Considering the third question

The name of the given molecule  is gotten according to longest carbon chain  = 4 (Prefix 'Butan')

Functional group = -OH (Suffix 'ol') at C-2

The IUPAC name is Butan-2-ol

3 0
2 years ago
20 points! Help please
Olin [163]

Answer: 2N2O3 -> 2N2 + 3O2

Explanation:

5 0
2 years ago
Read 2 more answers
The Ksp for BaCO3 is 5.1x10^-9. how many grams of BaCO3 will dissolve in 1000ml of water
Amanda [17]

Answer:

= 0.014 g of BaCO3

Explanation:

Let x = mol/L of BaCO3 that dissolve.  

This will give;

x mol/L Ba2+ and x mol/L CO32-  

But;

Ksp = 5.1x10^-9.

Therefore;

Ksp = 5.1 x 10^-9 = (x)(x)  

Thus;

x = molar solubility

  = √ (5.1 x 10^-9)

  = 7.1 x 10^-5 M  

Therefore;

Mass BaCO3 = 7.1 x 10^-5 M x 1 L x 197.34 g/mol

                      = 0.014 g

3 0
3 years ago
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