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Anarel [89]
3 years ago
6

What is the quotient and remainder of (4x^3-3x^2+x+7)/(x-2)

Mathematics
1 answer:
viva [34]3 years ago
7 0

Answer:

4x^2+11x+23 r53

Step-by-step explanation:

4x^3-3x^2+x+7 / x-2

2 | 4 -3  1   7

        8 22 46

___________

    4 11 23 53

This means 4x^2+11x+23 with a remainder of 53

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Rewrite the following equation in slope-intercept form.
Nana76 [90]

Answer:

y=1.7x + 1.3

Step-by-step explanation:

16x + 15y =20

therefore we make the variable stand on its own

15y = 20 - 16x

Divide both sides by the variable which is 15.

it will be y= 1.3 - 1 7x

so therefore the answer is :

y= 1.7x + 1.3

6 0
3 years ago
Order the following from least to greatest 0.222, 1/5, 0.02
lorasvet [3.4K]
1. Put all values in decimals

0.222=0.222

1/5= 0.2

0.02= 0.02

2. Order the cakes from least to greatest

0.02, 0.2, 0.222


Hope this helps!
6 0
3 years ago
Read 2 more answers
What is the answer to 2(17+3)=?
Effectus [21]
The answer is 40 easy
4 0
3 years ago
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In rectangle abcd, points p and q lie on side AB and DC respectively. Angle PMQ is a right angle, M is the midpoint of side BC a
nirvana33 [79]

Answer:

PM:MQ = 8:3.

Step-by-step explanation:

\rm \angle B\hat{M}P + 90^{\circ} + \angle C\hat{M}Q = 180^{\circ};

\implies \rm \angle B\hat{M}P + \angle C\hat{M}Q = 90^{\circ};

\implies \rm 90^{\circ} - \angle B\hat{M}P = \angle C\hat{M}Q.

Also,

\rm \angle B\hat{P}M = 90^{\circ} - \angle B\hat{M}P in right triangle PBM.

Thus \rm \angle{P\hat{B}M} = \angle C\hat{M}Q.

Additionally \rm \angle \hat{B} = 90^{\circ} = \angle \hat{C}.

Therefore \rm \triangle PBM \sim \triangle MCQ.

\rm \displaystyle BC = 2\;MC for M is the midpoint of segment BC.

\rm \displaystyle PB = \frac{4}{3}BC = \frac{8}{3}MC.

\rm \triangle PBM \sim \triangle MCQ implies that

\displaystyle \rm PM:MQ = PB:MC = 1:\frac{8}{3} = 8:3.

8 0
3 years ago
Mathhh time! No files or jokes pls
cestrela7 [59]

Answer:2.50cm

Step-by-step explanation:

6 0
3 years ago
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