Answer:
- Average age of the employees in 2003 = 57.216
- Average age of the employees in 2009 = 59.184
Step-by-step explanation:
We are given the function A(s) as;
A(s) = 0.328*s + 50 where s = number of years since 1981; that is,
s = 0 for 1981 and s = 9 for 1990
A(s) = the average age of an employee
- Now, the average age of the employees in 2003, A(22) = 0.328*22 + 50
Here s = 22 because 2003 - 1981 = 22 years
Therefore, average age of the employees in 2003 = 7.216 + 50 = 57.216 .
- Average age of the employees in 2009, A(28) = 0.328*28 + 50
Here, s = 28 because 2009 - 1981 = 28 years
Therefore, average age of the employees in 2009 = 9.184 + 50 = 59.184 .
P1 = (-7, -9)
P2 = (-2, 4)
ratio = 1/4
x = (-7 + 0.25(-2))/(1 + 0.25)
= (-7 - 0.5) / 1.25
= -7.5/1.25
= -6
y = (-9 + 0.25(4)) / (1 + 0.25)
y = (-9 + 1) / 1.25
y = -8/1.25
y = 6.4
The coordinate sof the point are (-6, 6.4)
The divisibility rule for 12: A number is divisible by 12 if it's divisible by both 6 and 2. The reason for this is because 12 = 6 x 2.