Answer:
Number of carbon, hydrogen, and oxygen atoms in sugar:
Explanation:
1) Given balanced chemical equation:
- Sugar(s) + 12O₂(g) → 11H₂O(g) + 12CO₂(g)
2) Mass conservation law: in a chemical reaction, the atoms are not created nor destroyed; they recombine to form new substances, so the number of atoms of each kind in the reactants is equal to the number of atoms of the same kind in the products.
3) Balance.
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Atom Products = Reactants
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C 12CO₂ ⇒ 12 = 12 in sugar
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H 11H₂O ⇒ 11 × 2 = 22 = 22 in sugar
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O 12CO₂ ⇒ 12 × 2 = 24 12 × 2 = 24 in O₂ + x in sugar
11H₂O ⇒ 11
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24 + 11 = 35 = 24 + x
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Solve for x: 35 = 24 + x ⇒ x = 35 - 24 = 11 ∴ 11 O atoms in sugar
Conclusion:
Number of carbon, hydrogen, and oxygen atoms in sugar:
