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Nesterboy [21]
3 years ago
5

* CRIMINOLOGY*

Physics
2 answers:
lukranit [14]3 years ago
7 0

A mandatory minimum is "a minimum sentence that must be imposed by a judge if an individual is found guilty of the crime".

Answer: Option B

<u>Explanation:</u>

Necessary minimum penalties are criminal sentences that involve minimum punishments determined by law. they'll apply to specific offences, specific offenders, or to explicit mixtures of offence and bad person characteristics.

The goal of those laws after they were developed was to push uniformity; it does not matter however strict or lenient your decide is, because the law and therefore the law alone determines the sentence you receive.

Setler [38]3 years ago
5 0

I think the answer is B.

Hope this helps.

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Which of the following is not true about tectonic plates
AlladinOne [14]

Answer:

Scientists have identified about a dozen major and several minor tectonic plates

6 0
2 years ago
Momentum of an object is determined to be 7.2 ×10 to the negative 3 kg
abruzzese [7]
Answer:

0.0072

Explanation

7.2x10^-3= 0.0072
6 0
2 years ago
If an object is thrown upward at 128 feet per second from a height of 76 feet, its height S after t seconds is given by the foll
faltersainse [42]
<h2>a) Average velocity in first 4 seconds is 64 ft/s upward</h2><h2>b) Average velocity in second 4 seconds is 63.5 ft/s downward</h2>

Explanation:

a) Given S(t) = 76 + 128t − 16t²

    s(0) = 76 + 128 x 0 − 16 x 0² = 76 ft

    s(4) = 76 + 128 x 4 − 16 x 4² = 332 ft

    Displacement in 4 seconds = 332 - 76 = 256 ft

    Time = 4 - 0 = 4 s

    \texttt{Velocity = }\frac{256}{4}=64ft/s

    Average velocity in first 4 seconds is 64 ft/s upward

a) Given S(t) = 76 + 128t − 16t²

    s(4) = 76 + 128 x 4 − 16 x 4² = 332 ft

    s(8) = 76 + 128 x 8 − 16 x 8² = 78 ft

    Displacement in 4 seconds = 78 - 332 = -254 ft

    Time = 4 - 0 = 4 s

    \texttt{Velocity = }\frac{-254}{4}=-63.5ft/s

    Average velocity in second 4 seconds is 63.5 ft/s downward

3 0
3 years ago
A screen is placed a distance dd to the right of an object. A converging lens with focal length ff is placed between the object
Elina [12.6K]

Answer:

2f

Explanation:

The formula for the object - image relationship of thin lens is given as;

1/s + 1/s' = 1/f

Where;

s is object distance from lens

s' is the image distance from the lens

f is the focal length of the lens

Total distance of the object and image from the lens is given as;

d = s + s'

We earlier said that; 1/s + 1/s' = 1/f

Making s' the subject, we have;

s' = sf/(s - f)

Since d = s + s'

Thus;

d = s + (sf/(s - f))

Expanding this, we have;

d = s²/(s - f)

The derivative of this with respect to d gives;

d(d(s))/ds = (2s/(s - f)) - s²/(s - f)²

Equating to zero, we have;

(2s/(s - f)) - s²/(s - f)² = 0

(2s/(s - f)) = s²/(s - f)²

Thus;

2s = s²/(s - f)

s² = 2s(s - f)

s² = 2s² - 2sf

2s² - s² = 2sf

s² = 2sf

s = 2f

8 0
3 years ago
Exercício:
zysi [14]

Answer:

a

Explanation:

a

a

a

a

a

a

a

a

a is the answer

7 0
3 years ago
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