Answer:
The slope is -7/4
Step-by-step explanation:
∵ 7x + 4y = 10
∵ y = mx + c ⇒ where m is the slope of the line
∴ Re-arrange the equation
∴ 4y = 10 - 7x ⇒ ÷4
∴ y = 10/4 - (7/4) x
∴ y = 5/2 - (7/4) x
∴ The slope is -7/4
Answer:
-9
Step-by-step explanation:
you'd add 2 to the -11 which would equal -9 and leave you with x=-9
I believe you meant: Use completing the square to determine the center and radius of the circle represented by this equation: <span>X^2+y^2-10x+6y=15
x^2 - 10x + 25 - 25 + y^2 + 6y + 9 - 9 = 15
Then:
(x-5)^2 + (y+3)^2 = 24 = 2sqrt(6)
This circle is centered at (5,-3) and has radius 2sqrt(6).</span>
Plug into y-y1=m(x-x1)
y+4=4(x-4)
Answer:
No, because it fails the vertical line test ⇒ B
Step-by-step explanation:
To check if the graph represents a function or not, use the vertical line test
<em>Vertical line test:</em> <em>Draw a vertical line to cuts the graph in different positions, </em>
- <em>if the line cuts the graph at just </em><em>one point in all positions</em><em>, then the graph </em><em>represents a function</em>
- <em>if the line cuts the graph at </em><em>more than one point</em><em> </em><em>in any position</em><em>, then the graph </em><em>does not represent a function </em>
In the given figure
→ Draw vertical line passes through points 2, 6, 7 to cuts the graph
∵ The vertical line at x = 2 cuts the graph at two points
∵ The vertical line at x = 6 cuts the graph at two points
∵ The vertical line at x = 7 cuts the graph at one point
→ That means the vertical line cuts the graph at more than 1 point
in some positions
∴ The graph does not represent a function because it fails the vertical
line test
