A=<span>Δv/t
a=change in velocity/time (27 would be negative because it's decelerating)
So
</span><span>Δv=-27m/s
</span>t=5
-27/5=-5.4m/s^2
Final answer: -5.4m/s^2
We have that the speed of the ice at the bottom is mathematically given as
v=1.8812m/s
<h3>The speed of the ice at the bottom </h3>
Question Parameters:
A 8.00 kg block of ice, released from rest
at the top of a 1.50-m-long frictionless ramp,
slides downhill, reaching a speed of 2.70 m/s
constant friction force of 10.0 N parallel to the surface of the ramp
Generally the equation for the Potential Energy is is mathematically given as
P.E=K.E+W_{fric}
Therefore
mgh=0.5mv^2+W_{fric}
Where
W_{fric}=F.S
W_{fric}=10*1.50
W_{fric}=15
And
mgh=0.5mv^2+
h=0.3719
Hence
0.5(8.00)(v^2)=(8.00)(9.8)(0.3719)-15
v^2=3.53924
v=1.8812m/s
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Answer:
2.8125 meters
Explanation:
I will assume 7.5 m/s
When the Kinetic Energy is entirely converted to Potential energy the max height will have been reached
KE = PE
1/2 m v^2 = mgh divide by m
1/2 v^2 = gh looking for h so divide both sides by
1/2 v^2 / g = h sub in the values using g = 10 m/s^2
1/2 ( 7.5 )^2 / 10 = 2.8125 m
Answer:
Ozone
Explanation:
The Ozone or green house gases prevents this Ultraviolent radiation from the sun.