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siniylev [52]
3 years ago
8

Giving brainliest!

Physics
1 answer:
Drupady [299]3 years ago
7 0

Answer:

  1. An object in space that has no motion has to be shoved to move in the first place because of <u>newton's first law of motion. </u>                          
  2.  A bowling ball will slow down and stop when rolled on a flat surface, like a street because of <u>rolling friction</u> which comes under<u> Newton's first law of motion.</u>                                  
  3. When a 100Kg astronaut throws a 9Kg bowling ball forward in space, she moves backward but slower, this is because of<u> Newton's third law of motion. </u>      

Explanation:

  • <u>This is due to Newton's first law of motion, explaining that an object in space that has no movement has to be moved to move in the first place.</u> There is no external force or gravitational force in space, so the body can stay at rest and be forced to move first.
  • <u>Explaining why a bowling ball, like a street, can slow down and stop when rolled on a flat surface.</u> This, again, is attributed to <u>Newton's first law of motion.</u> <u>Due to rolling friction, it happens.</u> The electrons on the surface of the ground in the atoms push against the electrons that touch the ground in the atoms on the surface of the ball as you roll a ball on the ground. A rolling ball stops when the surface on which it rolls opposes its motion. A ball rolling, due to friction, ceases.
  • <u>Explaining that when a 100 kg astronaut throws a 9 kg bowling ball forward in space, she travels backward but slower</u>, due to <u>Newton's third motion rule , </u>which states that when force is applied, each body exhibits equal and opposite reaction. In this case, the astronaut's mass is greater, so the ball's acceleration will be less than the astronaut 's mass (since the body's mass is inversely proportional to the acceleration). Therefore, because of the reverse direction and slowly because of no gravitational force in space, the girl shifts backward while tossing the ball forward in space.

<u> Newton's Law of Motion -  </u>

<u>FIRST  LAW -</u>  The first law of Newton states that if a body is at rest or moving in a straight line at a constant speed, it will stay at rest or continue to travel at constant speed in a straight line unless it is acted upon by a force.

<u>SECOND LAW -  </u> The second law of Newton is a quantitative explanation of the changes that a force can cause in a body 's motion. It states that the rate of change of a body's momentum in time is proportional to the force exerted on it in both magnitude and direction.  

<u>THIRD LAW -  </u>   The third law of Newton notes that they apply forces to each other when two bodies interact, which are equal in magnitude and opposite in direction. Often known as the law of action and reaction, the third law is. In analyzing static equilibrium problems, where all forces are balanced, this law is essential, but it also applies to bodies in uniform or accelerated motion.  

Hence , all the three explainations consist of newton's first and third  laws of motion.

                                                                         

                                             

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Explanation:

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8 0
3 years ago
An uncharged capacitor is connected to the terminals of a 4.0 V battery, and 6.0 μC flows to the positive plate. The 4.0 V batte
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Answer:

1 μC extra charge will be flow here

Explanation:

Given data

battery V1 = 4.0 V

flows Q1 =  6.0 μC

replace battery V2 = 7.0 V

to find out

what happen if we replace battery

solution

we apply here principal of capacitor

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Q2/Q1 = V2/ V1

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4 years ago
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Answer:

(a)  Radius of orbit will be =7.32\times10^6m

(b) Earth gravitational force will be =4.18\times 10^4N

(C) Height will be 0.92\times 10^6m

Explanation:

We have given

Mass of the earth, M=6\times 10^{24}kg

Mass of the satellite, m = 5600 kg

Radius of earth, R=6.4\times 10^6m

Time period T = 6200 sec

We know that \omega =\frac{2\pi }{T}=\frac{2\times 3.14}{6200}=0.00101rad/sec

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(b)

Force F=\frac{GMm}{R^2}=\frac{6.67\times 10^{-11}\times 6\times 10^{24}\times 5600}{(7.32\times 10^6)^2}=4.18\times 10^4N

(c)

Altitude h=radius\ of\ orbit-radius\ of\ earth=7.32\times 10^6-6.4\times 10^6=0.92\times 10^6m

8 0
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