Answer:
D. increases by a factor of 4.
Explanation:
General equation of SHM
Lets taken the general equation of the displacement given as
x = A sinω t
A=Amplitude ,t=time ,ω=natural frequency
We know that speed V
V= A ω cosωt
The mechanical energy of spring mass system
K=Spring constant
Now when Amplitude A become 2 times then the mechanical energy will become 4 times.
Therefore the answer is D.
Speed of the TRAX is given as 16 m/s so let say it is given as
now our speed towards the front end is given by 5 m/s so this is the relative speed of us with respect to TRAX
let say this speed is given as
now we need to find the speed with respect to someone standing outside the TRAX
so here we need to find the net speed in ground frame and hence we can use the formula of relative speed
so someone outside the TRAX will see our speed as 21 m/s
Answer:
<em>the smaller particle moves with speed of 8.706 m/s in the opposite direction to the bigger particle.</em>
<em></em>
Explanation:
Speed of the original particle = 13 m/s
We designate particles as A and B
The final weights of the component particles are
Particle A = 1.4 N
particle B = 1.9 N
The speed of the larger piece (particle B) = 29 m/s
We know that weight is the product of a body's mass and acceleration due to gravity g which is equal to 9.81 m/s^2, therefore, masses of the particles are
particle A = 1.4/9.81 = 0.143 kg
Particle B = 1.9/9.81 = 0.194 kg
The momentum of a body is the product of its mass and its velocity i.e
P = mv
This means that the mass of the particle before splitting is
0.143 kg + 0.194 kg = 0.337 kg
Momentum of the initial whole particle = mv
==> 0.337 x 13 = 4.381 kg-m/s
The bigger particle B remains horizontal, and has a momentum of
mv = 0.194 x 29 = 5.626 kg-m/s
<em>According to the conservation of momentum, the total initial momentum of a system must be equal tot the total final momentum of the system.</em>
Initial total momentum of the system = 4.381 kg-m/s (momentum of original particle before splitting)
Final total momentum of the system = Total momentum of the particles after splitting = 5.626 kg-m/s + ( 0.143 kg x )
where is the velocity of smaller particle A
final total momentum of the system = 5.626 + 0.143
Equating the two momenta of the system, we'll have
4.381 = 5.626 + 0.143
4.381 - 5.626 = 0.143
-1.245 = 0.143
= -1.245/0.143 =<em> -8.706 m/s</em>
<em>The negative sign indicates that the smaller particle moves in the opposite direction to the bigger particle</em>