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Vlada [557]
3 years ago
6

A large pendulum swings in the lobby of the United Nations building in New York City. The pendulum has a 91-kg gold-plated bob a

nd a length of 22.9 m. Assume g = 9.81 m/s2.
Part A
How much time does it take for the bob to swing from its maximum displacement to its equilibrium position?
Express your answer to three significant figures and include the appropriate units.
Physics
1 answer:
Dafna1 [17]3 years ago
6 0

Answer:

t = 2.40 s

Explanation:

It just told me

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horsena [70]

During the operation of fan we know that it is working on the electricity

So here when we connect the fan with electricity it uses the electrical energy and convert that energy into mechanical energy of fan

Fan uses this electrical energy to rotate the blades of fan and then it gives the high speed air to us

So here correct answer must be

B.  

motion energy

8 0
4 years ago
A spring has a force constant k, and an object of mass m is suspended from it. The spring is cut in half and the same object is
kenny6666 [7]

Answer:

f2/f1 = \sqrt{2}

Explanation:

From frequency of oscillation

f = 1/2pi *\sqrt{k/m}

Initially with the suspended string, the above equation is correct for the relation, hence

f1 = 1/2pi *\sqrt{k/m}

where k is force constant and m is the mass

When the spring is cut into half, by physics, the force constant will be doubled as they are inversely proportional

f2 = 1/2pi *\sqrt{2k/m}

Employing f2/ f1, we have

f2/f1 = \sqrt{2}

3 0
3 years ago
Richard is driving home to visit his parents. 135 mi of the trip are on the interstate highway where the speed limit is 65 mph .
Elis [28]
<h2>Answer:</h2>

He saves 13.2 minutes

<h2>Explanation:</h2>

Hey! The question is incomplete, but it can be found on the internet. The question is:

How many minutes did he save?

Let's call:

t_{1}:Time \ at \ speed \ 65mph \\ \\ t_{2}:Time \ at \ speed \ 73mph \\ \\ v_{1}=65mph \\ \\ v_{2}=73mph

We know that the 135 miles are on the interstate highway where the speed limit is 65 mph. From this, we can calculate the time it takes to drive on this highway. Assuming Richard maintains constant the speed:

v=\frac{d}{t} \\ \\ d:distance \\ \\ t:time \\ \\ v:velocity \\ \\ t_{1}=\frac{d}{v_{1}} \\ \\ t=\frac{135}{65} \\ \\ t_{1}=2.07 \ hours

Today he is running late and decides to take his chances by driving at 73 mph, so the new time it takes to take the trip is:

t_{2}=\frac{135}{73} \\ \\ t_{2}=1.85 \ hours

So he saves the time t_{s}:

t_{s}=t_{1}-t_{2}=2.07-1.85=0.22 \ hours

In minutes:

t_{s}=0.22h\left(\frac{60min}{1h}\right) \\ \\ \boxed{t_{s}=13.2min}

5 0
3 years ago
What is responsible for the unusual shape of a coastline
solong [7]
If a coastline has a very unusual shape it's normally caused by either a flood or dam.

hope this helps!
7 0
4 years ago
For the last part of the lab, you should have found the mass of the meter stick. So if a mass of 85 g was placed at the 2 cm MAR
Bond [772]

Answer:

272.89g

Explanation:

Find the diagram to the question in the attachment below;.

Using the principle of moment to solve the question which states that the sum of clockwise moment is equal to the sum of anticlockwise moment.

Moment = Force * Perpendicular distance

Taking the moment of force about the pivot.

Anticlockwise moment:

The 85g mass will move in the anticlockwise

Moment of 85g mass = 85×36.6

= 3111gcm

Clockwise moment.

The mass of the metre stick M situated at the centre (50cm from each end) will move in the clockwise direction towards the pivot.

CW moment = 11.4×M = 11.4M

Equating CW moment to the ACW moment we will have;

11.4M = 3111

M = 3111/11.4

M = 272.89g

The mass of the metre stick is 272.89g

5 0
4 years ago
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