<h2>Answer</h2>
Cost of lectures = $7.33 per hour
<h2>Explanation</h2>
Let 
the cost of the exam hours
Let 
be the cost of the workshop hours
Let 
be the cost of the lecture hours.
We know from our problem that exam hours cost twice as much as workshop, so:
equation (1)
We also know that workshop hours cost twice as much as lecture hours, so:
equation (2)
Finally, we also know that 3hr exams 24hr workshops and 12hr lectures cost $528, so:
equation (1)
Now, lets find the value of :
Step 1. Solve for in equation (3)
equation (4)
Step 2. Replace equation (1) in equation (4) and simplify
equation (5)
Step 3. Replace equation (2) in equation (5) and solve for
Cost of lectures = $7.33 per hour
Answer: See explanation
Step-by-step explanation:
a. how old is Cheryl?
Cheryl's age = d + 5
b. how old is Brandon?
d + 5 + 2
= d + 7
c. what was the difference in their ages 5 years ago?
Cheryl age five years ago = d
Brandon's age five years ago = d + 2
Difference = d + 2 - d = 2 years
d. what is the sum of their ages now?
Cheryl's age = d + 5
Brandon age = d + 7
Sum = d + 5 + d + 7
= 2d + 12
e. what will the sum of their ages be two years from now?
Two years from now,
Cheryl's age = d + 5 + 2 = d + 7
Brandon age = d + 7 + 2 = d + 9
Sum = d + 7 + d + 9
= 2d + 16
f. what will the difference of their ages be two years from now
Two years from now,
Cheryl's age = d + 5 + 2 = d + 7
Brandon age = d + 7 + 2 = d + 9
Difference = Brandon age - Cheryl age
= (d + 9) - (d + 7)
= 2 years.
Answer:
508.94
Step-by-step explanation:
Answer:
the 3 one is the correct answer
Step-by-step explanation:
Answer:
c/16
Step-by-step explanation:
