Original price of the item = $14.95
Price after discount = $13.79
Discount offered = original price - price after discount = 14.95- 13.79 = $1.16
Now let us find the percentage of discount offered.
Percentage discount is given by the formula:

Where MP= Marked price= original price
SP= selling price= price after discount

Percentage discount = 7.759 %
Since theirs no question...
The formula for PT:
a^+b^=c^
Answer:
f(x) = x * -3
Step-by-step explanation:
so, you have x and you have f(x), as you can see -4 turns into 12... you basically have to divide, multiply, add or subtract for each value to see what they have in common, here it's easy since -4 * -3 is 12, -2 * -3 is 6, 0 * -3 is 0, etc etc. hope it helped : )
We have the following function:
f (x) = x ^ 2
We have the following transformation:
Expansions and horizontal compressions
The graph of y = f (bx):
If 0 <b <1, the graph of y = f (x) expands horizontally by the factor of 1 / b.
Applying the transformation:
y = (0.2x) ^ 2
The factor is:
1 / b = 1 / 0.2 = 5
Answer:
b. expanded horizontally by a factor of 5
(I'm going to translate y' to dy/dx as it makes it easier to read for me, you could change it back if you wanted.)



(separate the variables)


(by letting c = ln k and using log laws)

(raise everything to power e)

(applying boundary conditions)
Particular solution: