Answer:
1 plain = $0.75; 1 cheese = $0.95; 1 super = $1.25
Step-by-step explanation:
We have three conditions
(1) 5P = 3S
(2) S = C + 0.30
(3) P = C – 0.20 Substitute (3) into (1)
=====
(4) 5(C – 0.20) = 3S Substitute (2) into (4)
5(C – 0.20) = 3(C + 0.30) Remove parentheses
5C – 1.00 = 3C + 0.90 Add 1.00 to each side
5C = 3C + 1.90 Subtract 3C from each side
2C = 1.90 Divide each side by 2
C = $0.95 Substitute C into Equation (2)
=====
S = 0.95 + 0.30
S = $1.25 Substitute C into Equation (3)
=====
P = 0.95 – 0.20
P = $0.75
1 plain = $0.75; 1 cheese = $0.95; 1 super = $1.25
The equation is already solved for the variable t To solve for any other variable simply rearrange theequation to have the indicated variable on one sideof the equals sign and everything else on the other. For example, to solve for a: t=an+b subtract b from both sidest-b = an divide both sides by n(t-b)/n = a Or: a = (t-b)/n Work in the same manner to solve for either b or n: b = t-an n = (t-b)/a
Answer:
he fraction 1/10 would be written as the decimal 0.1.
Step-by-step explanation:
Answer:
<h2>
<em><u>$23.40 </u></em></h2>
Step-by-step explanation:
<em><u>Given,</u></em>
Cost price of 8 cakes = $62.40
<em><u>So,</u></em>
Cost price of 1 cake = $ 
<em><u>Therefore,</u></em>
Cost price of 3 cakes
= $( × 3)
- <em>[On dividing 62.40 by 8]</em>
= $(7.80 × 3)
- <em>[On multiplying]</em>
= $23.40
<em><u>Hence,</u></em>
<em><u>The required cost of 3 cakes is $23.40 (Ans)</u></em>
Answer: B -4
Step-by-step explanation: I think it is B because -4 is smaller than A,C and D.
