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Ilya [14]
3 years ago
8

I have no idea please walk me though it in the comments and then answer

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
8 0
If it's like mosquitos and other water insects then its digging wells
also planting new trees might be a good idea too
aniked [119]3 years ago
6 0
I believe A. Hunting
Animals wouldn't be able to eat the bugs so the bug population would increase.

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What is the length of BC? Round to the nearest tenth.
Kay [80]

Answer:

BC ≈ 14.5 cm

Step-by-step explanation:

Using the sine ratio in the right triangle

sin65° = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{BC}{16} ( multiply both sides by 16 )

16 × sin65° = BC , then

BC ≈ 14.5 cm ( to the nearest tenth )

6 0
3 years ago
Emily was going to sell all of her stamp collection to buy a video game. After selling half of them she changed her mind. She th
siniylev [52]

Answer:

starts wuth 46, and sells half, so she has 23. then when she buys 17 more she then has 40.

if you are asked to show work its 46/2=23, then 23+17=40!

7 0
3 years ago
Read 2 more answers
Hallar el valor de x en 3(x-2)+4=x-5
kolezko [41]

Answer:

exact form 3/2 decimal  form 1.5 mixed number form 1 1/2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the
kodGreya [7K]

Answer:

  • p=0.7103 (4-game series)
  • p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters  n=4, p=0.6:

P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\  i=4,5,6,7

#We find probabilities for the different values of i:

P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659

Hence, probability of the stronger team winning overall is:

=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103

#Define Y as the random variable for winning 2/3 games.:

P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0
3 years ago
If the graph of the parent function f(x) = x is shifted 7 units up 5 left, what is the
Soloha48 [4]
F(x)= (x+5)+7 is the answer
6 0
3 years ago
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