Write an equation for a linear function whose graphs has the given characteristics. Passes through (-2,2) and (2,-8)

1 answer:

5 0

(-2,2)(2,-8)
slope = (-8 - 2) / (2 - (-2) = -10/4 = -5/2

y = mx + b
slope(m) = -5/2
(-2,2)...x = - 2 and y = 2
now we sub and find b, the y int
2 = -5/2(-2) + b
2 = 5 + b
2 - 5 = b
-3 = b

so ur equation is : y = -5/2x - 3

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mario62 [17]

Answer:

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