1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
wel
4 years ago
13

If f(x)=x-2 and g(x)=1/2x, find g(f(x))

Mathematics
2 answers:
Scilla [17]4 years ago
8 0

Answer:

hello :

If f(x)=x-2 and g(x)=1/2x,

g(f(x)) = g ( x - 2 )

          = 1/2(x-2)

g(f(x)) = (1/2)x - 1



Artyom0805 [142]4 years ago
3 0

Answer:

1/2x -1

Step-by-step explanation:

g(f(x) means put f(x) in for x in the function g(x)

g(f(x)) =

g(x) = 1/2 x

g(f(x) = 1/2 (f(x))

        =1/2 ((x-2))

        =1/2 x -1/2(2)

         =1/2 x-1

You might be interested in
Estimate it as a whole number
denis-greek [22]

Answer:

2

Step-by-step explanation:

First, you do the subtraction 120-21.4 which is 98.7. So since you know its x^7, the number isn't going to be big. By guessing and checking, we start with 2. 2^7 is 128. We know that 1^7 would just be 1, so the closest whole number would be two.

7 0
3 years ago
Can someone please help me with this problem? You need to find the value of x and y by using the strategy of ELIMINATION. Please
Setler [38]

Answer:

x = 136/35; y = -⁹/₁₀

Step-by-step explanation:

(1)         7x + 8y = 20

(2)        7x – 2y = 29       Subtract (2) from (1)

                  10y =  -9        Divide each side by 10

(3)                 y =  -⁹/₁₀     Substitute (3) into (1)

      7x - 2(-⁹/₁₀) = 29

      7x + 18/10  = 29                       Subtract 18/10 from each side

      7x              =      29 - 18/10

      7x              = (290 - 18)/10

      7x              =          272/10        Divide each side by 7

        x              =           272/70

        x              =           136/35

x = 136/35; y = -⁹/₁₀

Check:

(1) 7(136/35) + 8(-⁹/₁₀) = 20

      136/5    -   72/10 = 20

      136/5    -   36/5  = 20

                      100/5  = 20

                       20      = 20

(2) 7(136/35) – 2(-⁹/₁₀)  = 29

       136/5    +    18/10 = 29

       136/5    +      ⁹/₅    = 29

                        145/5  = 29

                        29       = 29

5 0
3 years ago
A Parallelogram must be a rectangle when it’s •A.)Diagnols are perpendicular •B.Diagnols are congruent •C. opposite sides are pa
Verizon [17]

Answer:A


Step-by-step explanation: the diagonals face each other making them perpendicular making both sides parallel to each other, being straight.


4 0
3 years ago
Read 2 more answers
The manager at Ben's Furniture Store is trying to figure out how much to charge for a table that just arrived. If the table was
bija089 [108]

Answer:

176.7

Step-by-step explanation:

8 0
3 years ago
Find the value of x.​
Lemur [1.5K]

Answer:

137

Step-by-step explanation:

6 0
3 years ago
Other questions:
  • Craig and Alissa are building a sandcastle on the beach. They each have a bucket. Craig holds 1/2 in his bucket and Alissa holds
    5·1 answer
  • Bonds payable should be reported as a long-term lThe Tony Hawk Skate Park has a 5-year installment loan with monthly payments of
    13·1 answer
  • 4. Find the surface area of a triangular prism with height 30 inches, and a right triangle base with side lengths 15 inches and
    9·1 answer
  • Evaluate the geometric series:<br> a1 =-1, r= 2, n= 7
    11·1 answer
  • the perimeter of a concession stand at the ballpark is 88 meters. the length is 4 meters longer than the width. what is the leng
    8·1 answer
  • Which statement is true for the values of Pand Q on this number line? + Q + -2 1 -4 -3 0 1 A 응 4 B. PxQ5 C P+Q&gt; -4 D P - Qo​
    6·1 answer
  • Neda sells televisions. She earns a fixed amount for each television and an additional $15 if
    11·1 answer
  • Solve for q.
    9·1 answer
  • Solve the equation 3x+4=20​
    7·2 answers
  • Ok plz help again. plzz
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!