Answer:
6
(4×n²) + (4×n¹) + (5×n^0) = 173
4n² + 4n + 5 = 173
4n² + 4n = 168
divide through by 4
n² + n - 42 = 0
n² + 7n - 6n - 42= 0
(n + 7)(n - 6) = 0
n = -7 or 6
but the solution is 6 since base is not negative.
X^0=1
5^0=1
1^n=1
answer is 1^4 and 5^0
This kind of question would actually be very dependable. So, let's suppose that we would have a number as 16. We would then have to divide this number by 4, mainly because we would want to find how many 4's would go into the number 16. But this would actually be an example. So, whatever math problem you may have, just remember this technique, how many numbers would go into that specific number.
Answer:
4
Step-by-step explanation:
It's a pythagorean triple