Ask question

Ask question

All categories

3 years ago

14

Consider a cylinder with radius 4.5 cm and a height of 12 cm. Describe how to calculate the surface area of the given cylinder a

nd what the surface area means.

2 answers:

kogti [31]3 years ago

8 0

Surface area of a cylinder = 2πrh+2πrsquared
= 2x3.14x4.5x12+2x3.14x20.25
= 339.12+127.17
= 466.29
Therefore, the surface area of a cylinder is 466.29cm

Luden [163]3 years ago

3 0

To find the surface area of a cylinder you need to multiply its circumference by its height, plus the areas of the bases. So, multiply the circumference by the height and add the bases : (π4.5×2)12+(π4.5²×2)=466.52cm².
Surface is the area of the outside part of 3D figure.

You might be interested in

If q is between 0 and 90 and tan(theta)= 7/8, find costheta

Leya [2.2K]

Answer:

hope it helps you see the attachment for further information.....

8 0

3 years ago

What is (2/9v - ( -1/3v + 5/9)

Airida [17]

-v/9-5/9 I really don't know if it's fully correct, but I hope it is!

7 0

3 years ago

The coordinates of the vertices of a polygon are (-2, 1). (-3, 3), (-1, 5), (2, 4), and (2, 1). What is the perimeter of the pol

kobusy [5.1K]

Answer:

$15.2\ units$

Step-by-step explanation:

step 1

Plot the vertices of the polygon to better understand the problem

we have

$A(-2, 1). B(-3, 3), C(-1, 5), D(2, 4),E(2, 1)$

using a graphing tool

The polygon is a pentagon (the number of sides is 5)

see the attached figure

The perimeter is equal to

$P=AB+BC+CD+DE+AE$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 2

<em>Find the distance AB</em>

$A(-2, 1). B(-3, 3)$

substitute in the formula

$d=\sqrt{(3-1)^{2}+(-3+2)^{2}}$

$d=\sqrt{(2)^{2}+(-1)^{2}}$

$d_A_B=\sqrt{5}=2.24\ units$

step 3

<em>Find the distance BC</em>

$B(-3, 3), C(-1, 5)$

substitute in the formula

$d=\sqrt{(5-3)^{2}+(-1+3)^{2}}$

$d=\sqrt{(2)^{2}+(2)^{2}}$

$d_B_C=\sqrt{8}=2.83\ units$

step 4

<em>Find the distance CD</em>

$C(-1, 5), D(2, 4)$

substitute in the formula

$d=\sqrt{(4-5)^{2}+(2+1)^{2}}$

$d=\sqrt{(-1)^{2}+(3)^{2}}$

$d_C_D=\sqrt{10}=3.16\ units$

step 5

<em>Find the distance DE</em>

$D(2, 4),E(2, 1)$

substitute in the formula

$d=\sqrt{(1-4)^{2}+(2-2)^{2}}$

$d=\sqrt{(-3)^{2}+(0)^{2}}$

$d_D_E=\sqrt{9}\ units$

$d_D_E=3\ units$

step 6

<em>Find the distance AE</em>

$A(-2, 1).E(2, 1)$

substitute in the formula

$d=\sqrt{(1-1)^{2}+(2+2)^{2}}$

$d=\sqrt{(0)^{2}+(4)^{2}}$

$d_A_E=\sqrt{16}\ units$

$d_A_E=4\ units$

step 7

Find the perimeter

$P=AB+BC+CD+DE+AE$

substitute the values

$P=2.24+2.83+3.16+3+4=15.23\ units$

Round to the nearest tenth of a unit

$P=15.2\ units$

6 0

3 years ago

The diameter of the circle that a shot-putter stands in is 7 ft. What is the approximate area of the circle?

Andrei [34K]

Answer:

24?

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

X - 4y = 28<br> 2x + y =2

Tresset [83]

X - 4y = 28
2x + y = 2

solve for x
y= -2x + 2
y= x/4 - 7

solve for system of equations
(4,-6)
x= 4, y= -6

7 0

2 years ago