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dolphi86 [110]
3 years ago
14

Assume the line of best fit for a data set is given by y=22x+32. What data points are predicted by the line of best fit? Check a

ll that apply.
a.(10,480)
b.(5,142)
c.(8,208)
d.(7,154)
Mathematics
1 answer:
malfutka [58]3 years ago
3 0
Hi. You have to do trial and error with each of the choices to see which of those apply. They are points on the given function y=22x+32 that lie on point (x,y). Just substitute the x-and y values to the function.

a. (10,480) => x = 10, y = 480
     y = 480 = 22(10) + 32
     480 = 252 (does not apply)

b. (5,142) => x = 5, y = 142
     y = 142= 22(5) + 32
     142 = 142 (apply)

c. (8,208) => x = 8, y = 208
     y = 208 = 22(8) + 32
     208 = 208 (apply)

d. (7,154) => x = 7, y = 154
     y = 154 = 22(7) + 32
     154 = 186 (does not apply)

The answer is B and C.
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A cone of radius 10 cm and height 16 cm is divided into two parts by a plane through the midpoint of its
bazaltina [42]

Answer:

The ratio of their volumes (the top to bottom half) is 1/7

Step-by-step explanation:

The given parameters are;

The radius, r, of the cone = 10 cm

The height of the cone = 16 cm

The point at which the cone is divided = The midpoint of the its axis and parallel to its base

The ratio of the of the volume of the two parts is given as follows;

The volume, V of the entire cone = 1/3 × Base area (π·r²) × Height, h

Therefore;

V = 1/3 × π × 10² × 16 =1600·π/3 =  1675.52 cm³

The height at which the cone is divided = 16/2 = 8 cm

The height, h₁ of the uppermost divided cone = 8 cm

The ratio of the radius to the height of the cone = 10/16 = 5/8

The radius r₁, of the uppermost divided cone = The height of the uppermost divided cone × The ratio of the radius to the height of the cone

∴ r₁ = 8 × 5/8 = 5 cm

The volume, V₁, of the uppermost divided cone = 1/3 × (π·r₁²) × h₁

∴ V₁ = 1/3 × π × 5² × 8 = 200·π/3 = 209.44 cm³

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The volume of the lower cone, V₂ =  V - V₁

V₂ =  1675.52 cm³ - 209.44 cm³ = 1400·π/3 = 1466.1 cm³

The ratio of their volumes V₁ : V₂ = V₁/V₂ = (200·π/3)/(1400·π/3) = 209.44/1466.1 = 1/7.

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Sven can type 30 words per minute.How many words would he type in 20 minutes?
saveliy_v [14]
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Which shapes can be drawn with two opposite angles equal to 105°
sertanlavr [38]

Answer:

see the explanation

Step-by-step explanation:

we know that

A shape with two opposite angles equal to 105° could be a quadrilateral, a parallelogram, a rhombus or a trapezoid

Because

<em>A quadrilateral</em>: A quadrilateral is a four-sided polygon. The sum of the interior angles in any quadrilateral must be equal to 360 degrees

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If the quadrilateral have two opposite angles equal to 105°, then the sum of the other two interior angles must be equal to

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<em>A parallelogram</em>: A Parallelogram is a flat shape with opposite sides parallel and equal in length. Opposite angles are congruent and consecutive angles are supplementary

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If the parallelogram have two opposite angles equal to 105°, then the measure of each of the other two congruent interior angles must be equal to

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<em>A rhombus</em>: A Rhombus is a flat shape with 4 equal straight sides. A rhombus looks like a diamond. All sides have equal length. Opposite sides are parallel. Opposite angles are congruent and consecutive angles are supplementary

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<em>A trapezoid</em>: A trapezoid is a 4-sided flat shape with straight sides that has a pair of opposite sides parallel

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If the trapezoid have two opposite angles equal to 105°, then the sum of the other two interior angles must be equal to

360^o-2(105^o)=150^o

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