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allochka39001 [22]
3 years ago
10

PLEASE HELP FOR TEST TO GET GRADE TO PASSING

Mathematics
1 answer:
pashok25 [27]3 years ago
8 0
Cuocitis vivvbivi it such in
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WHY IS EDGENUITY SO HARD?!?!??!?!
Cerrena [4.2K]

Answer:

because you have to work, and i'm doing edinuity

Step-by-step explanation:

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3 years ago
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the length of the sides of a square are initially 0 cm and increase at a constant rate of 11 cm per second. suppose the function
Likurg_2 [28]

The function of the area of the square is A(t)=121t^{2}

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

\frac{dx}{dt} = 11 \frac{cm}{sec}

⇒x=11t

Area of square=(length of side)^{2}

Area of square=(11t)^{2}{as the length of side is 11t}{varies by time}

Area of square=121t^{2}

Therefore,The function of the area of the square is A(t)=121t^{2}

Learn more about The function of the area of the square is A(t)=121t^{2}

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

\frac{dx}{dt} = 11 \frac{cm}{sec}

⇒x=11t

Area of square=(length of side)^{2}

Area of square=(11t)^{2}{as the length of side is 11t}{varies by time}

Area of square=121t^{2}

Therefore,The function of the area of the square is A(t)=121t^{2}

Learn more about area here:

brainly.com/question/27683633

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3 0
2 years ago
A car's wheels spins at 1000 revolutions per minute. The diameter of the wheels is 23 inches. You want to know how fast the car
ch4aika [34]

Answer:

72,220 inches per  minute

Step-by-step explanation:

A car's wheels spins at 1000 revolutions per minute. The diameter of the wheels is 23 inches.

1 revolution = 2\pi radians

\frac{theta}{tome}=\frac{1000 \ revolution}{1 \ minuite} = \frac{1000* 2\pi }{1} =\frac{2000\pi}{1 \ minute}

Speed V= \frac{r*theta}{t}

r is the radius , theta is the angle and t is the time

We know diameter = 23  , then radius = 23/2

Speed V= \frac{23}{2}*\frac{2000\pi}{1}

Value of pi = 3.14

speed = 23000* 3.14= 72220 inches/ minute


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e=-7

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