Question

I need help with these 3 questions ASAP. please give me a step by step explanation.

Answer 1

For number 2. The pilot flew 4 circuits and in total by the 5th day he flew 14 right?

Answer 2

Answer:

1) first term = 2

Step-by-step explanation:

1)  n =14 ;   d = 6 ;  Sum = 574

    Sum =n/2 * (2a + (n-1)d)

     574 = 14/2 * (2a + (14-1) * 6)

     574   = 7 * (2a + 13 * 6)

  574   = 7 * (2a +  78)

   574/ 7 = 2a + 78

     82    = 2a + 78

 82 - 78 = 2a

   4 = 2a

 a = 4/2

a =2

2) No.of circuits on first day = 14 - 12  = 2 circuits

Total by the end of fifth day  = 2 + 5 +8 +11 +14 = 40

3) n = 20 ;   a = 32768

  r = term 2  / term 1 = 16384 / 32768 = 1/2

 nth term = ar^(n-1)

20th term = 32768 * (1/2)^19

                 = 32768 * (1/ 524288)

                 = 32768 / 524288

                  = 1/16