I need help with these 3 questions ASAP. please give me a step by step explanation.
2 answers:
For number 2. The pilot flew 4 circuits and in total by the 5th day he flew 14 right?
Answer:
1) first term = 2
Step-by-step explanation:
1) n =14 ; d = 6 ; Sum = 574
Sum =n/2 * (2a + (n-1)d)
574 = 14/2 * (2a + (14-1) * 6)
574 = 7 * (2a + 13 * 6)
574 = 7 * (2a + 78)
574/ 7 = 2a + 78
82 = 2a + 78
82 - 78 = 2a
4 = 2a
a = 4/2
a =2
2) No.of circuits on first day = 14 - 12 = 2 circuits
Total by the end of fifth day = 2 + 5 +8 +11 +14 = 40
3) n = 20 ; a = 32768
r = term 2 / term 1 = 16384 / 32768 = 1/2
nth term = ar^(n-1)
20th term = 32768 * (1/2)^19
= 32768 * (1/ 524288)
= 32768 / 524288
= 1/16
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Mario made the mistake on everything and he needs help
|4-24x|=52
24x=56
2.333~ is your answer
Answer:
The ratio is 10 : 1, or 10 to 1
Step-by-step explanation:
C = what ever the algebraic pharse is standing for c can equal to what ever number there is
60=4/5x
4/5=0.8
60/0.8=75
X=75
