Question

How many solutions does the following equation have? ln(x2 + 4x − 5) = 0

Answer 1

Alrighty
remember
$log_a(b)=c$ means $a^c=b$
and
$ln(x)=log_e(x)$
and
$x^0=1$ for all real values of x
so

$ln(x^2+4x-5)=0$ means
$log_e(x^2+4x-5)=0$ means
$e^0=x^2+4x-5$ which simplifies to
1=x²+4x-5
minus 1 both sides
0=x²+4x-6
use quadratic formula or complete the square
$x=-2+\sqrt{10}$ and $x=-2-\sqrt{10}$
2 solutions