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nikdorinn [45]
3 years ago
7

Please help me on this geometry i’ll mark u the brainliest

Mathematics
1 answer:
kicyunya [14]3 years ago
5 0

Answer:

<h2>               XN = 6</h2>

Step-by-step explanation:

If XY is bisector of angle AXN then:   \dfrac{YN}{AY}=\dfrac{XN}{AX}

\dfrac4{12}=\dfrac{XN}{18}\\\\XN=\dfrac4{12}\cdot18\\\\XN=6                                                            

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(5, 3) and (6, r) m = -1
Rzqust [24]

Answer:

r = 2

Step-by-step explanation:

(2-3)/(6-5)

= -1/1

= -1

6 0
3 years ago
Need help ()()()()()((;(;
Gwar [14]

Answer:

20%

Step-by-step explanation:

4/20 = x/100

100*4 =400

400/20 = 20

so

4/20 = 20/100

8 0
3 years ago
Read 2 more answers
Need help ASAP!!! Will mark brainliest
Papessa [141]

A=148°

B=148°

Step-by-step explanation:

180-38=148°

because A and B are equal, they're both 148°

7 0
3 years ago
In ΔABC, point M is the midpoint of side AB and point D is the midpoint of segment MC. Prove that the area of ΔADC= the area of
Anna11 [10]
A line segment from a vertex to the midpoint of the opposite side is a "median". A median divides the area of the triangle in half, as it divides the base in half without changing the altitude.
AAMC is half AABC. AADC is half AAMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
ABMC is half AABC. ABMD is half ABMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
Then, AADC = 1/4 AABC = ABMC, so AADC = ABMC by the transitive property of equality.
8 0
3 years ago
hii i need help with a geometry problem. i'll mark you brainliest!! please please help i really need to solve this.
k0ka [10]

Answer:

∠ ABC = 81° , ∠ FEC = 90°

Step-by-step explanation:

Since AB ≅ BC then Δ ABC is isosceles.

The median BE is therefore

The angle bisector of ∠ ABC and

BE bisects AC at right angles.

Thus

∠ ABE = ∠ CBE = 40° 30' , then

∠ ABC = 2 × 40° 30' = 81°

Since BE is perpendicular to AC then

∠ FEC = 90°

8 0
3 years ago
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