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2 years ago

Write tge following numbers expanded forms. 23900068407

Mathematics

1 answer:

ladessa [460]2 years ago

5 0

Answer:

Step-by-step explanation:

20000000000+3000000000+900000000+60000+8000+400+7

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Divide: 28.324 : 0.4<br> A 0.7081<br> B 7,081<br> C 708.1<br> D 70.81

valina [46]

Answer:

D-70.81

Step-by-step explanation:

I did the math, this should be correct.

Good luck!

3 0

2 years ago

Read 2 more answers

In a study, 36% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop

steposvetlana [31]

Answer:

0.3907

Step-by-step explanation:

We are given that 36% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.

i.e. $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

Formula : $P(x=r)=^nC_r p^r q ^ {n-r}$

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

$P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!} (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=0.390748$

Hence the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.3907

5 0

3 years ago

What is the measure, in degrees, of ∠x in the figure?

gizmo_the_mogwai [7]

Answer:

I believe the answer is 127 degrees.

Step-by-step explanation:

Please give brainliest.

8 0

3 years ago

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What is 1 2/3 multiplied by 4 1/2

horrorfan [7]

Change the mixed numbers into improper fractions:
5/3 X 9/2

Reduce - the 3 and 9 can be simplified
5/1 X 3/2

multiple numerators and denominators
15/2

Not sure how you need the answer - i would change it into a mixed number
7 1/2

3 0

3 years ago

Three different whole numbers add up to 31.

lubasha [3.4K]

Let's find the least possibilities:

First number: 6
Second number: 8
Third number: 10

6 + 8 + 10 = 24

Now we can see that we are still missing 31 - 24 = 7.

7 can be gained by adding 3 and 4, so:

First number: 6 + 3 = 9
Second number: 8 + 4 = 12
Third number: 10

9 + 12 + 10 = 31

5 0

3 years ago

Write tge following numbers expanded forms. 23900068407​

Write tge following numbers expanded forms. 23900068407