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Naily [24]
3 years ago
15

Mr. Lyons is laying tile for the rectangular floor of a hotel lobby. The floor will be 38 tiles wide and 112 tiles long. He has

a total of 4,400 tiles. Which explains whether or not he has enough tiles for the entire floor?
A. No, he does not have enough tiles. He needs 4,456 tiles, so he needs 56 more.
B. No, he does not have enough tiles. He needs 4,600 tiles, so he needs 200 more.
C. Yes, he has enough tiles. He needs only 4,146 tiles and will have 254 left over. D. Yes, he has enough tiles. He needs only 4,256 tiles and will have 144 left over.
Mathematics
1 answer:
Dahasolnce [82]3 years ago
4 0
GG lolololololololololololo
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A man runs around a square park and covers 1km in five rounds.<br> What is the area of the park?
Allisa [31]

Answer:

The area of the park is equal to 2,500 square meters.

Step-by-step explanation:

Given that a man runs around a square park and covers 1km in five rounds, the following calculation must be performed to determine the area of the park:

Assuming that the park was square in shape, to calculate its area its base must be multiplied by its height (which are equal).

Thus, if in 5 laps the man runs 1 km, for each lap he will run 200 meters (1000/5). Thus, dividing 200 by the 4 sides of the square, we get 50 meters (200/4). Therefore, since 50 x 50 is equal to 2,500, the area of the park is equal to 2,500 square meters.

6 0
3 years ago
You and a friend walk away from a tree in opposite directions each traveling 15 yards. You were walking due east and then turned
LenKa [72]

Answer:

2nd friend heading west

Step-by-step explanation:

This is actually pretty easy to explain.

You and a friend are near a tree and decide to walk away from it. At the beggining you walked 15 yards and your friend too, and then, there's the turn of event. You walked 8 yards toward north east, and your friend 8 yards towards south west.

The key to know which is further from the tree is the angle of turning of both. We need to calculate the component in x from both persons, and then, add it to the previous 15 yards. This way we will know who is further.

Let's begin with the 1°, the one who's heading east:

X = 15 + 8 cos45° = 20.66 yards

Now the friend heading west:

X = 15 + 8 cos40° = 21.13 yards

With these results we can conclude that the 2nd friend is further from the tree.

Hope this helps

7 0
3 years ago
Find the midpoint with the endpoints (1,2) (7,2)
den301095 [7]

Answer:

(4,2)

Step-by-step explanation:

The x coordinate of the midpoint is the sum of the x coordinates divided by 2

( 1+7)/2 = 8/2 = 4

The y coordinate of the midpoint is the sum of the y coordinates divided by 2

( 2+2)/2 = 4/2 = 2

The midpoint is (4,2)

3 0
3 years ago
Read 2 more answers
What is the measure of XYZ​
lorasvet [3.4K]

Answer:

B

Step-by-step explanation:

The arc XZ is twice the measure of the inscribed angle XYZ , that is

arc XZ = 2 × 60° = 120°

The complete circumference = 360° , thus

arc XYZ = 360° - arc XZ = 360° - 120° = 240° → B

6 0
3 years ago
Read 2 more answers
For the problem 1/5g- 1/10- g + 1 3/10g -1/10, Tyson created an equivalent expression using the following steps. 1/5g+-1g+1 3/10
professor190 [17]

The true statements are:

  • Tyson's expression is not equivalent to the original expression
  • The equivalent expression is:\frac{1}{2}g- \frac 1{5}

<h3>What are equivalent expressions?</h3>

Equivalent expressions are expressions that have equal values

The original expression is given as:

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10}

Collect like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac 15g - g + 1 \frac{3}{10}g- \frac 1{10}  -\frac{1}{10}

Evaluate the like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac{1}{2}g- \frac 1{5}

Tyler's equivalent expression is given as:

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10}

Collect like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = \frac15g-g+ 1 \frac3{10}g-\frac 45g-\frac 1{10}+1 \frac{1}{10}

Evaluate the like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = -\frac 3{10}g

The simplified expressions of the original expression, and Tyson's equivalent expressions are not equal.

Hence, Tyson's expression is not equivalent to the original expression

Read more about equivalent expressions at:

brainly.com/question/9603710

3 0
2 years ago
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