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mojhsa [17]
2 years ago
8

use the principles of atomic structure and/or chemical bonding to explain each of the following. in each part, your answers must

include references to both substances. the atomic radius of li is larger than that of be. the second ionization energy of k is greater than the second ionization energy of ca. the carbon-to-carbon bond energy in c2h4 is greater than it is in c2h6. the boiling point of cl2 is lower than the boiling point of br2.
Chemistry
1 answer:
denpristay [2]2 years ago
4 0

The magnitude of dispersion forces in Br2 is greater than the magnitude of dispersion forces in Cl2.

Atomic radius decreases across the period but increases down the group. As more shells are added to the atom, the repulsion between electrons increases. Across the group, more electrons are added without increase in the number of shell hence atomic radius decreases across the period due to increase in the size of the nuclear charge. Therefore,  the atomic radius of Li is larger than that of Be.

Ionization energy is a periodic trend that increases across the period but decreases down the group. Since the outermost electron is further from the nucleus due to screening of inner electrons, ionization energy decreases down the group. Across the period, the size of the nuclear charge increases hence ionization energy increases across the period.

For K, the second electron is removed from an inner shell which requires a very large amount of energy. In Ca, the second electron is removed from the valence shell which requires a lesser amount of energy. Therefore, the second ionization energy of K is greater than the second ionization energy of Ca.

The carbon to carbon bond in C2H4 is a double bond which has a greater bond enthalpy than the single bond in C2H6. As such, the carbon to carbon bond in C2H4 has a greater bond energy than the carbon to carbon bond in C2H6.

The boiling point of Cl2 is lower than the boiling point of Br2 because Br2 is larger than Cl2 hence the magnitude of dispersion forces in Br2 is greater than the magnitude of dispersion forces in Cl2.

Learn more: brainly.com/question/11155928

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Examples of polar covalent bonds
mars1129 [50]
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8 0
3 years ago
Given these reactions, X ( s ) + 1 2 O 2 ( g ) ⟶ XO ( s ) Δ H = − 668.5 k J / m o l XCO 3 ( s ) ⟶ XO ( s ) + CO 2 ( g ) Δ H = +
qwelly [4]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -1052.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

X(s)+\frac{1}{2}O_2(g)+CO_2(g)\rightarrow XCO_3(s)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) X(s)+\frac{1}{2}O_2(g)\rightarrow XO(s)    \Delta H_1=-668.5kJ

(2) XCO_3(s)\rightarrow XO(s)+CO_2     \Delta H_2=+384.3kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times \Delta H_1]+[1\times (-\Delta H_2)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-668.5))+(1\times (-384.3))=-1052.8kJ

Hence, the \Delta H^o_{rxn} for the reaction is -1052.8 kJ.

7 0
3 years ago
A chemical reaction produces 653 550 kj of energy as heat in 142.3min. calculate the rate of energy transferred in kj per minute
miskamm [114]

We have the value of  

Total energy produced in the chemical reaction=653 550 KJ  

Time needed=142.3min  

To calculate the rate of energy transfer, that is the amount of energy produced per minute.  

Rate of energy transfer=\frac{Total energy produced}{Time needed}

=\frac{653 550}{142.3}

=4592.76 KJ min⁻¹

So, the rate of energy transfer is 4592.76 KJ min⁻¹.

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