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mojhsa [17]
2 years ago
8

use the principles of atomic structure and/or chemical bonding to explain each of the following. in each part, your answers must

include references to both substances. the atomic radius of li is larger than that of be. the second ionization energy of k is greater than the second ionization energy of ca. the carbon-to-carbon bond energy in c2h4 is greater than it is in c2h6. the boiling point of cl2 is lower than the boiling point of br2.
Chemistry
1 answer:
denpristay [2]2 years ago
4 0

The magnitude of dispersion forces in Br2 is greater than the magnitude of dispersion forces in Cl2.

Atomic radius decreases across the period but increases down the group. As more shells are added to the atom, the repulsion between electrons increases. Across the group, more electrons are added without increase in the number of shell hence atomic radius decreases across the period due to increase in the size of the nuclear charge. Therefore,  the atomic radius of Li is larger than that of Be.

Ionization energy is a periodic trend that increases across the period but decreases down the group. Since the outermost electron is further from the nucleus due to screening of inner electrons, ionization energy decreases down the group. Across the period, the size of the nuclear charge increases hence ionization energy increases across the period.

For K, the second electron is removed from an inner shell which requires a very large amount of energy. In Ca, the second electron is removed from the valence shell which requires a lesser amount of energy. Therefore, the second ionization energy of K is greater than the second ionization energy of Ca.

The carbon to carbon bond in C2H4 is a double bond which has a greater bond enthalpy than the single bond in C2H6. As such, the carbon to carbon bond in C2H4 has a greater bond energy than the carbon to carbon bond in C2H6.

The boiling point of Cl2 is lower than the boiling point of Br2 because Br2 is larger than Cl2 hence the magnitude of dispersion forces in Br2 is greater than the magnitude of dispersion forces in Cl2.

Learn more: brainly.com/question/11155928

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One mole of Ca is equal to how many atoms​
Irina18 [472]

Answer:

1 mole of calcium contains 6.023 \times 10^{23} atoms.

Explanation:

1 mole is the amount of a substance that contains exactly 6.023\times 10^{23} constituent particles. 1 mole of a substance is always equal to the atomic mass of the element.

Hence, 1 mole of calcium will also have 6.023\times 10^{23} atoms.

Number of atoms in 1 mole calcium = 6.023 \times 10^{23} atom

4 0
3 years ago
Na2CO3(aq) + CaCl2(aq) — 2 NaCl(aq) + CaCO3(s)
attashe74 [19]

Answer:

100 mL

Explanation:

Given data:

Mass of CaCO₃ produced = 2.00 g

Molarity of CaCl₂ = 0.200 M

Volume of CaCl₂ needed = ?

Solution:

Chemical equation:

Na₂CO₃  + CaCl₂    →      2NaCl + CaCO₃

First of all we will calculate the number of moles of CaCO₃.

Number of moles = mass/molar mass

Number of moles = 2.00 g / 100.09 g/mol

Number of moles = 0.02 mol

Now we will compare the moles of CaCO₃ and CaCl₂.

              CaCO₃          :            CaCl₂

                   1                :               1

                 0.02           :              0.02

Thus, 0.02 moles of CaCl₂ react,

Volume of CaCl₂ reacted:

Molarity = number of moles / volume in L

0.200 M = 0.02 mol / volume in L

Volume in L = 0.02 mol / 0.200 M

Volume in L = 0.1 L

Volume in mL:

0.1 L × 1000 mL/1L

100 mL

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