Because they react, hope this helps
the concentration when 0.065 moles of NaNO3 are dissolved in enough water to make 150 ml of solution is calculated as follows
concentration (molarity) = moles/volume x1000
molarity is therefore= 0.065moles/ 150 x1000 = 0.43M
The base dissociation constant or Kb is a value used to measure
the strength of a specific base in solution. To determine the percent ionization
of the substance we make use of the Kb given. Methylamine or CH3NH2 when
in solution would form ions:
CH3NH2 + H2O < = > CH3NH3+ + OH-
Kb is expressed as follows:
<span>
Kb = [OH-] [CH3NH3+] / [CH3NH2]
Where the terms represents the concentrations of the acid and the ions.
By the ICE table, we can calculate the equilibrium concentrations,
CH3NH2 CH3NH3+
OH-
I 1.60 0
0
C -x +x
+x
--------------------------------------------------
E 1.60-x x
x
Kb = [OH-] [CH3NH3+] / [CH3NH2] = </span> 3.4×10−4
<span> 3.4×10−4</span> = x^2 / 1.60-x
Solving for x,
x = [OH-] = 0.023 M
pH = 14 + log 0.023 = 12.36
Therefore, the first option is the closest one.
Answer:
<h2>675 mmHg</h2>
Explanation:
The new pressure can be found by using the formula for Boyle's law which is
Since we're finding the new pressure
We have
We have the final answer as
<h3>675 mmHg</h3>
Hope this helps you