Answer:
a)  F = 2.66 10⁴ N, b)   h = 1.55 m
Explanation:
For this fluid exercise we use that the pressure at the tap point is
Exterior
           P₂ = P₀ = 1.01 105 Pa
inside
          P₁ = P₀ + ρ g h
the liquid is water with a density of ρ=1000 km / m³
          P₁ = 0.85   1.01 10⁵ + 1000   9.8  5
          P₁ = 85850 + 49000
          P₁ = 1.3485 10⁵ Pa
the net force is
          ΔP = P₁- P₂
          Δp = 1.3485 10⁵ - 1.01 10⁵
          ΔP = 3.385 10⁴ Pa
 Let's use the definition of pressure
          P = Fe / A
          F = P A
the area of a circle is
          A = pi r² = [i d ^ 2/4
let's reduce the units to the SI system
          d = 100 cm (1 m / 100 cm) = 1 m
          F = 3.385 104 pi / 4 (1) ²
          F = 2.66 10⁴ N
b) the height for which the pressures are in equilibrium is
         P₁ = P₂
         0.85 P₀ + ρ g h = P₀
         h =  
 
         h =  
         h = 1.55 m
 
        
             
        
        
        
Here is your answer:
First find the notations:
2×10^-3
=0002
And...
2.5×10^4=25000
Then divide:
0002÷25000=8E-9
Your answer:
=8 x 10-8
        
             
        
        
        
Answer:
v = 83.1 % of speed of light 
Explanation:
given,
T_e is the earth time = 2.7 s
T_s is the ship time = 1.5 s
we know,

where c is the speed of light
v is the speed of the rock star moving



squaring both side


v = 0.831 c
v = 83.1 % of speed of light