Question

A 0.15 kg baseball is hit by a baseball bat. Right before it is hit, the ball’s speed is 30 m/s, and right after it is hit, the ball’s speed is 50 m/s in the opposite direction. What is the magnitude of the net impulse that is applied to the ball?
10.5 kg?m/sA. 4.5 kg?m/sB. 12.0 kg?m/sC. 7.5 kg?m/sD. 3.0 kg?m/s

Answer 1

Answer:

Impulse will be 12 kgm/sec

So option (b) will be correct option

Explanation:

We have given mass of the baseball m = 0.15 kg

Ball speed before hit $v_1=30m/sec$

Ball speed after hitting  $v_2=-50m/sec$ ( negative direction due to opposite direction )

We have to find the impulse

We know that impulse is equal; to the change in momentum

So change in momentum = $m(v_1-v_2)=0.15(30-(-50))=0.15\times 80=12kgm/sec$

So option (b) will be correct option