In a closed system, energy in form of heat (work) can be exchanged but not matter.
The answer to your question is C.
Hope it helped!
The conservation of momentum states that the total momentum in a system is constant if there is no external force acting on the system. The total momentum in the gun bullet system is 0 so it must stay that way.
The momentum of the bullet is mv = 0.015*500=7.5
The momentum of the gun must be the same to keep the total momentum of the system equal to zero, so we know that p = 7.5 for the gun.
Substituting this in we get:
7.5=3.1x
x=7.5/3.1
x=2.42
So the speed of the gun is 2.4m/s.
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Answer:
45.9m
Explanation:
Given parameters:
Final velocity = 30m/s
Initial velocity = 0m/s
Unknown:
Time it takes for the object of fall = ?
Height of fall = ?
Solution:
For the first problem, we use the equation below to solve for t;
V = U + gt
V is the final velocity
U is the initial velocity
g is the acceleration due to gravity
t is the time taken
30 = 0 + 9.8 x t
30 = 9.8t
t = = 3.1s
Now, height of fall;
V² = U² + 2gH
30² = 0² + 2 x 9.8 x H
900 = 19.6H
H = 45.9m
Answer:
t₂> t₁
Explanation:
When the package reaches the braking ramp it gives a constant acceleration, which slows it down in distance d, let's use the kinematic equations to find this acceleration ration, when the package stops or speed is zero
v²= v₀₁² + 2 a₁ d
0 = v₀₁² + 2 a₁ d
a1 = v₀₁² / 2d
This constant acceleration since it depends on the characteristics of the braking section,
Let's look for the time it takes to stop
v = vo - a₁ t
t = v₀₁ / a₁
Now let's calculate the time for the second package
t₂ = v₀₂ / a₁ (1)
As the initial velocity in the second case is greater and the acceleration is constant, the time must increase
t₂> t₁
We can calculate this value, write the equation for the two cases
v² = v₀₁² + 2 a₁ d
v² = v₀₂² + 2 a₁ 2d
v₀₁² + 2 a₁ d = v₀₂² + 2 a₁ 2d
v₀₂² - v₀₁² = 2 a₁ (2d - d)
v₀₂² = v₀₁² + 2 a₁ d
We substitute in 1
t₂ =1 / a₁ RA (v₀₁² + 2 a₁ d)
t₂ = RA (v₀₁₂ / a₁² + 2d / a₁)
t₂ = Ra (t₁² + 2 d / a₁)
t₂> t₁