Answer:
0.9378
Explanation:
Weight (W) of the rider = 100 kg;
since 1 kg = 9.8067 N
100 kg will be = 980.67 N
W = 980.67 N
At the slope of 12%, the angle θ is calculated as:
The drag force D = Wsinθ
where;
A = 0.9 m²
V = 15 m/s
∴
Drag coefficient
The following shows the forces acting on a box. Explain how you calculate the net force in any direction on the box.
1 answer:
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Here we have perfectly inelastic collision. Perfectly inelastic collision is type of collision during which two objects collide, stay connected and momentum is conserved. Formula used for conservation of momentum is:
In case of perfectly inelastic collision v'1 and v'2 are same.
We are given information:
m₁=0.5kg
m₂=0.8kg
v₁=3m/s
v₂=2m/s
v'₁=v'₂=x
0.5*3 + 0.8*2 = 0.5*x + 0.8*x
1.5 + 1.6 = 1.3x
3.1 = 1.3x
x = 2.4 m/s
In case of perfectly inelastic collision v'1 and v'2 are same.
We are given information:
m₁=0.5kg
m₂=0.8kg
v₁=3m/s
v₂=2m/s
v'₁=v'₂=x
0.5*3 + 0.8*2 = 0.5*x + 0.8*x
1.5 + 1.6 = 1.3x
3.1 = 1.3x
x = 2.4 m/s
Answer:
218.5 N
Explanation:
In order for the sled to be in equilibrium along the vertical direction, the forces acting along this direction must be balanced. So the equilibrium equation is:
where
N is the normal force
F = 50 N is the force that pulls the sled
is the angle between the force and the horizontal, so
is the component of F acting along the vertical direction
(mg) is the weight of the sled, with
m = 25 kg being the mass of the sled
g = 9.8 m/s^2 is the acceleration due to gravity
Solving the formula for N, we find