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SIZIF [17.4K]
3 years ago
13

3

Mathematics
2 answers:
Sedaia [141]3 years ago
7 0

21 students; 3/4 ; Possible explanation: 75% corresponds to 21 students.

So, 21 students met their reading goal. The fraction 75/100 represents 75%.

Therefore, 75/100, or 3/4, of 28 students met their reading goal.

Please mark Brainliest!

laila [671]3 years ago
3 0

Answer:

Step-by-step explanation:

Number of students who met their reading goal = 75% of 28

=\frac{75}{100}*28=\frac{3}{4}*28\\\\=3*7=21

Fraction: 21 students out of 28 met their reading goal

so,

\frac{21}{28}=\frac{3}{4}

3/4students met their reading goal

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Is -36/12 an integer whole number natural rational or irrational ?
jeka57 [31]

Answer:

integer

Step-by-step explanation:

5 0
2 years ago
In what number base is the addition 456+24+225=1050​
jasenka [17]

This additition is false

the true answer is 705

Its base on my understanding:)

<h3>꧁✰_______❀Edilyn❀_______✰꧂</h3><h3 />

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<em>Just please, idols ,if we are going to answer questions here on brainly, don't do the ones from the internet, then just copy and paste </em>

<em>Just please, idols ,if we are going to answer questions here on brainly, don't do the ones from the internet, then just copy and paste You can search on the internet but make your own sentence okay? Thank you </em>

8 0
3 years ago
Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 ​students, she finds 2 w
irina1246 [14]

Answer:

A 95​% confidence interval for the proportion of students who eat cauliflower on​ Jane's campus is [0.012, 0.270].

Step-by-step explanation:

We are given that Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 ​students, she finds 2 who eat cauliflower.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

                              P.Q.  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of students who eat cauliflower

           n = sample of students

           p = population proportion of students who eat cauliflower

<em>Here for constructing a 95% confidence interval we have used a One-sample z-test for proportions.</em>

<u>So, 95% confidence interval for the population proportion, p is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                   of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

Now, in Agresti and​ Coull's method; the sample size and the sample proportion is calculated as;

n = n + Z^{2}__(\frac{_\alpha}{2})

n = 24 + 1.96^{2} = 27.842

\hat p = \frac{x+\frac{Z^{2}__(\frac{\alpha}{2}_)  }{2} }{n} = \hat p = \frac{2+\frac{1.96^{2}   }{2} }{27.842} = 0.141

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

 = [ 0.141 -1.96 \times {\sqrt{\frac{0.141(1-0.141)}{27.842} } } , 0.141 +1.96 \times {\sqrt{\frac{0.141(1-0.141)}{27.842} } } ]

 = [0.012, 0.270]

Therefore, a 95​% confidence interval for the proportion of students who eat cauliflower on​ Jane's campus [0.012, 0.270].

The interpretation of the above confidence interval is that we are 95​% confident that the proportion of students who eat cauliflower on​ Jane's campus is between 0.012 and 0.270.

7 0
3 years ago
I need help with division help please
tigry1 [53]
24/6=4 24/8=3 4/4=1 12/6=2 48/8=6 give me a thanks and message me all the other ones u want me to answer
7 0
3 years ago
How many feet are in 84 yards. (im really bad at converting) :(
Gre4nikov [31]
1 yard = 3 feet, so we would do 3×84, which is 252.

There are 252 feet in 84 yards.
7 0
3 years ago
Read 2 more answers
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