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Temka [501]
3 years ago
11

A water bottle holds Fraction 5 over 8 liter of water when it is Fraction 3 over 4 full. Which statement best describes the quot

ient of 5 over 8division sign3 over 4?
Mathematics
1 answer:
butalik [34]3 years ago
6 0

This question is incomplete because it lacks the appropriate statements required to answer the question.

Complete Question

A water bottle holds Fraction 5 over 8 liter of water when it is Fraction 3 over 4 full.

Which statement best describes the quotient of 5 over 8division sign3 over 4?

a) The maximum amount of water the bottle can hold is Fraction 6 over 5 liters.

b) The amount of water that can be still poured in the bottle is Fraction 5 over 6 liter.

c) The amount of water that can be still poured in the bottle is Fraction 6 over 5 liters.

d) the maximum amount of water that the bottle can hold is Fraction 5 over 6 liter.

Answer:

d) the maximum amount of water that the bottle can hold is Fraction 5 over 6 liter.

Step-by-step explanation:

From the question we are told:

A water bottle holds Fraction 5 over 8 liter of water

Mathematically = 5/8 Liters

when it is Fraction 3 over 4 full.

Mathematically = 3/4

Which statement best describes the quotient of 5 over 8division sign3 over 4

The above statement is expressed mathematically as:

= 5/8 ÷ 3/4

= 5/8 / 3/4

Hence, this is calculated as:

= 5/8 × 4/3

= 20/24

= 5/6

Therefore, the statement that best describes this is option d) the maximum amount of water that the bottle can hold is Fraction 5 over 6 liter.

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Answer:

51.72\text{ cells per hour}

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

C)

So, we are given that the quadratic curve of the trend is the function:

P(t)=6.10t^2-9.28t+16.43

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]

Expand:

P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]

Differentiate. Use the power rule:

P'(t)=6.10(2t)-9.28(1)

Simplify:

P'(t)=12.20t-9.28

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

P'(5)=12.20(5)-9.28

Multiply:

P'(5)=61-9.28

Subtract:

P'(5)=51.72

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.

And we're done!

7 0
3 years ago
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