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3 years ago

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How do you solve this one 10x^2-25=x^2

1 answer:

solong [7]3 years ago

4 0

10x^2 - 25 = x^2
Take the square root of each side.

$\sqrt{x^2} = \sqrt{10x^2 - 25}$
x = 10x - 5i

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Answer:

P(at most four) = 0.00960541

Step-by-step explanation:

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Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

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This is:

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{19,0}.(0.5)^{0}.(0.5)^{19} = 0.00000191$

$P(X = 1) = C_{19,1}.(0.5)^{1}.(0.5)^{18} = 0.00003624$

$P(X = 2) = C_{19,2}.(0.5)^{2}.(0.5)^{17} = 0.00032616$

$P(X = 3) = C_{19,3}.(0.5)^{3}.(0.5)^{16} = 0.00184822$

$P(X = 4) = C_{19,4}.(0.5)^{4}.(0.5)^{15} = 0.00739288$

Then

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.00000191 + 0.00003624 + 0.00032616 + 0.00184822 + 0.00739288 = 0.00960541$

So

P(at most four) = 0.00960541

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