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Paul [167]
3 years ago
15

In △ABC, m∠A=27 °, c=14 , and m∠B=25 °. Find a to the nearest tenth.

Mathematics
1 answer:
Gnesinka [82]3 years ago
3 0

Answer:

a = 8.1

Step-by-step explanation:

Firstly, since we have a triangle, automatically, we have 3 interior angles

Mathematically the sum of these angles = 180

A + B + C = 180

27 + 25 + C = 180

52 + C = 180

C = 180-52

C = 128

We use the sine rule to find a

The sine rule posits that the ratio of a side to the sine of the angle facing that side is equal for all the sides of a triangle

Thus, mathematically according to the sine rule;

c/Sin C = a/Sin A

14/sin 128 = a/sin 27

a = 14sin27/sin 128 = 8.0657

which to the nearest tenth is 8.1

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You are to graph   <span>y = |1.6x – 2| – 3.2.  I trust you know that the graph of y=|x| is v-shaped, opening up, with vertex at (0,0).

Let's rewrite </span><span>y = |1.6x – 2| – 3.2 by factoring 1.6 out of  |1.6x - 2|:

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This tells us that the vertex of   </span><span>y = |1.6x – 2| – 3.2   is at (2/1.6,  -3.2).  If you need an explanation of why this is, please ask.

Plot the vertex at (1.25, -3.2).
Find the y-intercept:  Let x = 0 in  </span><span>y = |1.6x – 2| – 3.2 and find y:

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The y-intercept is located at 0, -1.2)

Plot this y-intercept.

Now draw a straight line from the vertex to this y-intercept.  Reflect that line across the y-axis to obtain the other half of the graph.</span>
8 0
3 years ago
Read 2 more answers
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