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Paul [167]
3 years ago
15

In △ABC, m∠A=27 °, c=14 , and m∠B=25 °. Find a to the nearest tenth.

Mathematics
1 answer:
Gnesinka [82]3 years ago
3 0

Answer:

a = 8.1

Step-by-step explanation:

Firstly, since we have a triangle, automatically, we have 3 interior angles

Mathematically the sum of these angles = 180

A + B + C = 180

27 + 25 + C = 180

52 + C = 180

C = 180-52

C = 128

We use the sine rule to find a

The sine rule posits that the ratio of a side to the sine of the angle facing that side is equal for all the sides of a triangle

Thus, mathematically according to the sine rule;

c/Sin C = a/Sin A

14/sin 128 = a/sin 27

a = 14sin27/sin 128 = 8.0657

which to the nearest tenth is 8.1

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<h3>There are 2 answers: choice C, choice D</h3>

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Explanation:

32% = 32/100 = 0.32

32% of 400 = 0.32*400 = 400(0.32), which adds onto the original 400 to get 400+400(0.32). This is why choice D is one of the answers.

We can factor out the GCF 400 to go from 400+400(0.32) to 400(1+0.32) which then simplifies to 400(1.32) or just 400*1.32. This shows choice C is the other answer. Using a calculator,

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