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4 years ago

In △ABC, m∠A=27 °, c=14 , and m∠B=25 °. Find a to the nearest tenth.

Mathematics

1 answer:

Gnesinka [82]4 years ago

3 0

Answer:

a = 8.1

Step-by-step explanation:

Firstly, since we have a triangle, automatically, we have 3 interior angles

Mathematically the sum of these angles = 180

A + B + C = 180

27 + 25 + C = 180

52 + C = 180

C = 180-52

C = 128

We use the sine rule to find a

The sine rule posits that the ratio of a side to the sine of the angle facing that side is equal for all the sides of a triangle

Thus, mathematically according to the sine rule;

c/Sin C = a/Sin A

14/sin 128 = a/sin 27

a = 14sin27/sin 128 = 8.0657

which to the nearest tenth is 8.1

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3 years ago

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We know that

cos A=adjacent side angle A/hypotenuse
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the answers are
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cot A=adjacent side angle A/opposite side angle A
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opposite side angle A=10 units
cot A=24/10------> cot A=12/5

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