Answer:
The slope is
. The slope means that the amount of money in the account is decreasing at a rate of $
every week.
Step-by-step explanation:
Given coordinates are
We need to find the slope of the graph, and explain what does slope means for this graph.
The formula for computing slope
is
Where
and
are the point on the line.
Let us plug points
in the equation
Here, the negative sign of slope
represents that the value of the function (budget) is decreasing, with an increase in time (week).
The slope is
. The slope means that the amount of money in the account is decreasing at a rate of $
every week.
Answer:
In the form of
Y= mx+c
Y= 1/2x +2
m = 1/2
Step-by-step explanation:
A linear equation in it's standard form is in the format
Y= mx+c
Where m is the slope and c is the y intercept
Let's use these two points to determine both the slope and the equation
(2, 3), (4,4)
Slope= (y2-y1)/(x2-x1)
Slope= (4-3)/(4-2)
Slope= 1/2
Equation of the linear function
(Y-y1)/(x-x1)= m
(Y-3)/(x-2)= 1/2
2(y-3) = x-2
2y -6 = x-2
2y= x-2+6
2y= x+4
Y= 1/2x +2
Answer:
We accept H₀
Step-by-step explanation:
Normal Distribution
size sample n = 69
sample mean 18.94
standard deviation 8.3
Is a one tailed-test to the left we are traying of find out is we have enough evidence to say that the mean is less than 20 min.
1.-Test hypothesis H₀ ⇒ μ₀ = 20
Alternative hypothesis Hₐ ⇒ μ₀ < 20
2.- Critical value
for α = 0.1 we find from z Table
z(c) = - 1.28
3.-We compute z(s)
z(s) = [ ( μ - μ₀ ) / (σ/√n) ⇒ z(s) = [( 18.94 - 20 )*√69)/8.3]
z(s) = ( -1.06)*8.31/8.3
z(s) = - 1.061
4.- We compare
z(c) and z(s) -1.28 > -1.061
Then z(c) > z(s)
z(s) in inside acceptance region so we accept H₀
Answer:
D
Step-by-step explanation:
The expression is 
We can follow the rule of "PEMDAS" here.
PEMDAS = Parenthesis, Exponents, Multiply, Divide, Add, Subtract
So, we first need to deal with Parenthesis. Next,
There aren't any exponents, so we deal with Multiplication of 7 and 3.
Then addition/subtraction.
Hence, the first step, from the answer choices, would be D, multiply 7 and 3