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laila [671]
4 years ago
14

Just number 8 please help

Chemistry
2 answers:
Black_prince [1.1K]4 years ago
8 0

Answer:

Just go on Google.

Explanation:

It is quite busy now &people are asking too many questions.

azamat4 years ago
7 0

Answer:

The answer is protons

Explanation:

hope it helps :3

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The Answer to the question is insulators.
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3 years ago
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In a 1.0× 10–6 M solution of Ba(OH)2(aq) at 25 °C, identify the relative molar amounts of these species.
Marysya12 [62]
Thank you for posting your question here. Below is the solution:

HNO3 --> H+ + NO3- 
<span>HNO3 = strong acid so 100% dissociation </span>
<span>** one doesn't need to find the molarity of water since it is the solvent </span>

<span>0M HNO3 </span>
<span>1x10^-6M H3O+ </span>
<span>1x10^-6M NO3- </span>
<span>1x10^-8M OH-.....the Kw = 1x10^-14 = [H+][OH-] </span>
<span>you have 1x10^-6M H+ so, 1x10^-14 / 1x10^-6 = 1x10^-8M OH- </span>


<span>1x10^-6 Ba(OH)2 = strong base, 100% dissociation </span>
<span>1x10^-6M Ba2+ </span>
<span>2x10^-6M OH- since there are 2 OH- / 1 Ba2+ </span>
<span>0M Ba(OH)2 </span>
<span>5x10^-9M H3O+</span>
4 0
4 years ago
Is this correct? This is stoichiometry.
Viefleur [7K]
Yes it’s is bc I said so
7 0
3 years ago
How can both the pitcher and the glass contain the same volume of iced<br> tea?
erma4kov [3.2K]

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Explanation:

7 0
3 years ago
Name the following compound. Group of answer choices 2-methyl-4-pentyne 4-methyl-3-propyl-1-pentyne 3-isopropyl-1-hexyne 1-nonyn
Fynjy0 [20]

The question is incomplete, the complete question is shown in the image attached

Answer:

3-isopropyl-1-hexyne

Explanation:

Organic compounds can be named from the structure of the compound. The name reveals the arrangement of atoms and bonds in the molecule.

If we look at the compound in the question, we will notice that the parent chain contains six carbon atoms, the triple bond is located at position 1 and the isopropyl substituent is attached to carbon 3.

Hence the proper name of the compound becomes, 3-isopropyl-1-hexyne.

7 0
3 years ago
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