The three main types of lipids are triglycerides, steroids and phospholipids
Answer is: 3,4
Chemical reaction: HNO₂ + NaOH → NaNO₂ + H₂O.
c₀(HNO₂) = 1,2 M = 1,2 mol/dm³.
c₀(NaNO₂) = 0,8 M = 0,8 mol/dm³.
V₀(HNO₂) = V₀(NaNO₂) = 1 dm³ = 1 L.
c₀(NaOH) = 0,5 M = 0,5 mol/dm³.
n₀(HNO₂)= 1,2 mol/dm³ · 1 dm³ = 1,2 mol.
n₀(NaNO₂) = 0,8 mol/dm³ · 1 dm³ = 0,8 mol.
V(NaOH) = 400 mL · 0,001 dm³/mL = 0,4 dm³.
n₀(NaOH) = c₀(NaOH) · V₀(NaOH).
n₀(NaOH) = 0,5 mol/dm³ · 0,4 dm³ = 0,2 mol.
n(HNO₂) = 1,2 mol - 0,2 mol = 1 mol.
n(NaNO₂) = 0,8 mol + 0,2 mol = 1 mol.
c(HNO₂) = 1 mol ÷ 1,4 dm³ = 0,714 mol/dm³.
c(NaNO₂) = 1 mol ÷ 1,4 dm³ = 0,714 mol/dm³.
pH = pKa + log (c(HNO₂) / c(NaNO₂)).
pH = 3,4 + log (0,714 mol/dm³ / 0,714 mol/dm³) = 3,4.
Answer:
There are 6.024 grams of sodium hydroxide in the solution.
Explanation:
Moles of sodium hydroxide = n
Volume of sodium hydroxide solution = 251.0 mL = 0.251 L
Molarity of the sodium hydroxide = 0.600 M
Mass of 0.1506 moles of NaOH :
There are 6.024 grams of sodium hydroxide in the solution.
Answer:
Option B. Sodium
Explanation:
In the formation of NaCl, sodium loses and electron while chlorine receives the electron as illustrated below:
Na —> Na+ + e- ....... (1)
Cl + e- —> Cl- ......... (2)
Now, combining equation 1 and 2 we have:
Na + Cl + e- —> Na+ + Cl- + e-
Cancelling the electron from both side, we obtained:
Na + Cl —> Na+Cl-
From the above illustration, we see clearly that sodium loses electron
In order to synthesize a complex organic molecule, the
chemist should at least illustrate or imagine the bonds that are in need to be
cut down or to separate in order to obtain the compound that can be easily
changed.
