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tamaranim1 [39]
3 years ago
13

10 mixture use in home for daily life ​

Chemistry
1 answer:
zalisa [80]3 years ago
6 0

Answer:

bro what

Explanation:

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konstantin123 [22]

The three main types of lipids are triglycerides, steroids and phospholipids

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3 years ago
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One liter of a buffer composed of 1.2 m hno2 and 0.8 m nano2 is mixed with 400 ml of 0.5 m naoh. what is the new ph? assume the
enyata [817]
Answer is: 3,4
Chemical reaction: HNO₂ + NaOH → NaNO₂ + H₂O.
c₀(HNO₂) = 1,2 M = 1,2 mol/dm³.
c₀(NaNO₂) = 0,8 M = 0,8 mol/dm³.
V₀(HNO₂) = V₀(NaNO₂)  = 1 dm³ = 1 L.
c₀(NaOH) = 0,5 M = 0,5 mol/dm³.
n₀(HNO₂)= 1,2 mol/dm³ · 1 dm³ = 1,2 mol.
n₀(NaNO₂) = 0,8 mol/dm³ · 1 dm³ = 0,8 mol.
V(NaOH) = 400 mL · 0,001 dm³/mL = 0,4 dm³.
n₀(NaOH) = c₀(NaOH) · V₀(NaOH).
n₀(NaOH) = 0,5 mol/dm³ · 0,4 dm³ = 0,2 mol.
n(HNO₂) = 1,2 mol - 0,2 mol = 1 mol.
n(NaNO₂) = 0,8 mol + 0,2 mol = 1 mol.
c(HNO₂) = 1 mol ÷ 1,4 dm³ = 0,714 mol/dm³.
c(NaNO₂) = 1 mol ÷ 1,4 dm³ = 0,714 mol/dm³.
pH = pKa + log (c(HNO₂) / c(NaNO₂)).
pH = 3,4 + log (0,714 mol/dm³ / 0,714 mol/dm³) = 3,4.
6 0
4 years ago
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How many grams of sodium hyrdioxde are in 251.0ml f 0.600m
Furkat [3]

Answer:

There are 6.024 grams of sodium hydroxide in the solution.

Explanation:

Molarity=\frac{Moles}{Volume (L)}

Moles (n)=Molarity(M)\times Volume (L)

Moles of sodium hydroxide = n

Volume of sodium hydroxide solution = 251.0 mL = 0.251 L

Molarity of the sodium hydroxide = 0.600 M

n=0.600 M\times 0.251 L=0.1506 mol

Mass of 0.1506 moles of NaOH :

40 g/mol\times 0.1506 mol = 6.024 g

There are 6.024 grams of sodium hydroxide in the solution.

4 0
3 years ago
In sodium chloride, which atom loses an electron?
Fittoniya [83]

Answer:

Option B. Sodium

Explanation:

In the formation of NaCl, sodium loses and electron while chlorine receives the electron as illustrated below:

Na —> Na+ + e- ....... (1)

Cl + e- —> Cl- ......... (2)

Now, combining equation 1 and 2 we have:

Na + Cl + e- —> Na+ + Cl- + e-

Cancelling the electron from both side, we obtained:

Na + Cl —> Na+Cl-

From the above illustration, we see clearly that sodium loses electron

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3 years ago
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An organic chemist plans for the synthesis of a complex organic molecule by
VladimirAG [237]

In order to synthesize a complex organic molecule, the chemist should at least illustrate or imagine the bonds that are in need to be cut down or to separate in order to obtain the compound that can be easily changed.

7 0
4 years ago
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