Fluoride is an anion of Fluorine

What this means is that the two have the same number of protons (9), but Fluoride has 10 electrons compared to Fluorine's 9.

So the answers are:
Protons - 9
Neutrons - 9
Electrons - 10
Atomic Number - 9
Atomic Mass - 19 g/mol

5 0

3 years ago

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Atoms of metals tend to1) lose electrons and form negative ions2) lose electrons and form positive ions3) gain electrons and for

timofeeve [1]

Answer:

2) lose electrons and form positive ions

Explanation:

Metals are generally electropositive elements due to the fact that they lose electrons to their non-metal counterparts and hence, form CATIONS or positively charged atoms. Non-metals, on the contrary, gains electrons and become negatively charged i.e form anions. These ions combine to form stable ionic compounds.

This electron-losing characteristics of metals make them have properties that includes: good conductors of electricity and heat, being lustrous etc.

4 0

3 years ago

8.310x10^2 – 7.210x10^1 [?]x10^[?]

alisha [4.7K]

Answer:

$7.589\times 10^{2}$

Explanation:

The expression can be solved mathematically as follows:

1) $8.310\times 10^{2}-7.210\times 10^{1}$ Given

2) $8.310\times 10^{1+1} - 7.210\times 10^{1}$ Definition of sum

3) $(8.310\times 10^{1})\times 10^{1}-7.210\times 10^{1}$ $a^{m+n} = a^{m}\cdot a^{n}$ /Associative property

4) $(8.310\times 10^{1}-7.210)\times 10^{1}$ Distributive property

5) $(83.100-7.210)\times 10^{1}$ Multiplication

6) $75.89\times 10^{1}$ Subtraction.

7) $(7.589\times 10^{1})\times 10^{1}$ Multiplication/Associative property

8) $7.589\times (10^{1}\times 10^{1})$ Associative property

9) $7.589\times 10^{2}$ $a^{m+n} = a^{m}\cdot a^{n}$ /Result

7 0

3 years ago

The ph of a solution for which [OH]= 1.0 x 10^-4 is? A 10 B 14 C 11 D 9 E 7

zhenek [66]

To find pH, use the following formula ---> pH= - log [H+]

so first we need to calculate the [H+] concentration using the OH concentration. to do this, we need to use this formula--> 1.0x10-14= [H+] X [OH-], so we solve for H+ and plug in

[H+]= 1.0X10-14/[OH-]---> 1.0 x 10-14/ 1.0 x 10-4= 1.0 x 10-10

now that we have the H+ concentration, we can solve of pH

pH= -log (1.0x10-10)= 10

answer is A

8 0

3 years ago