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3 years ago

Does anyone understand this?

Chemistry

1 answer:

Nikolay [14]3 years ago

7 0

From start:

Joule, J, calorie,

Example 1: 120 J / 4.184 = 28.68 cal
Example 2: 1200 cal * 4.184 = 5020.8 J

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The acid dissociation constant Ka of boric acid (H3BO3) is 5.8 times 10^-10. Calculate the pH of a 4.4 M solution of boric acid.

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Answer: The pH of a 4.4 M solution of boric acid is 4.3

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$H_3BO_3\rightarrow H^+H_2BO_3^-$

at t=0 cM 0 0

at eqm $c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

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$K_a=5.8\times 10^{-10}$

Putting in the values we get:

$5.8\times 10^{-10}=\frac{(4.4\times \alpha)^2}{(4.4-4.4\times \alpha)}$

$(\alpha)=0.000011$

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3 years ago

A nitrox ii gas mixture for scuba diving contains oxygen gas at 53 atm and nitrogen gas at 94 atm . what is the total pressure,

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