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4 years ago

Does anyone understand this?

Chemistry

1 answer:

Nikolay [14]4 years ago

7 0

From start:

Joule, J, calorie,

Example 1: 120 J / 4.184 = 28.68 cal
Example 2: 1200 cal * 4.184 = 5020.8 J

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Which half-reaction correctly shows the oxidation of iron

pishuonlain [190]

Answer:

What is the oxidation half reaction for iron?

The two elements involved, iron and chlorine, each change oxidation state; iron from +2 to +3, chlorine from 0 to -1. There are then effectively two half-reactions occurring. These changes can be represented in formulas by inserting appropriate electrons into each half-reaction: Fe2+ → Fe3+ + e.

Hope this helps..

8 0

3 years ago

By which process aqua fortis is manufactured

kap26 [50]

Answer: Aqua fortis is also known as Nitric Acid

Explanation: and the process in making aqua fortis is THE OSTWALDS PROCESS

detailed explanation by me

ammonia is also used in this process, which is reacted with oxygen and water and a catalyst platinum.

HOPE THIS HELPSS!!!

7 0

3 years ago

For each of the esters provided, identify the alcohol and the carboxylic acid that reacted.

Veronika [31]

Answer:

52. The alcohol USED => methanol, CH3OH

The carboxylic acid USED => propanoic acid, CH3CH2COOH.

53. The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

Explanation:

52. To obtain Methyl propanoate, CH3CH2COOCH3, we simply react propanoic, CH3CH2COOH and methanol, CH3OH together as shown below:

CH3CH2COOH + CH3OH —> CH3CH2COOCH3 + H2O

The alcohol used: methanol, CH3OH

The carboxylic acid used: propanoic acid, CH3CH2COOH.

53. To obtain Ethyl methanoate, HCOOCH2CH3, we simply react

Formic acid, HCOOH and ethanol, CH3CH2OH together as show below:

HCOOH + CH3CH2OH —> HCOOCH2CH3 + H2O

The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

7 0

3 years ago

2Na(s) + Cl2(g) - 2NaCl(s) + 822 kj

pychu [463]

Answer:

Is there any other part to this question? If not I'm pretty sure the answer is 205.5 kJ

Explanation:

8 0

3 years ago

Read 2 more answers

Need help with this Stoichiometry question

Inessa [10]

Hi!

<u>HCl is the limiting reactant.</u>

From the equation, we understand that 1 mole of Mg(OH)2 will react with 2 moles of HCl for the reaction to be complete. To find the limiting reactant we need to see which molecule is in lower quantity (in terms of moles and not mass)

Calculating the number of moles of Mg(OH)2 given

Using the formula, number of moles= mass / molecular mass

number of moles = 50.6 / 58 = ~ 0.872

Calculating the number of moles of HCl given

Number of moles = 45 / 36.5 = ~ 1.232

There are several ways to use this information to calculate the limiting reactant. In our case, we can subtract the number of moles of Mg(OH)2 from the number of moles of HCl and check for the remainder.

If it is more than 0.872, then HCl would be in excess, with Mg(OH)2 being the limiting reactant; however, if the remainder is less than 0.872, it would mean <em>HCl is the limiting reactant.</em>

1.232- 0.872 = 0.36

As 0.36 < 0.872 , we see that HCl is the limiting reagent.

NOTE: this is in the case that the moles of HCl needed to complete the reaction is twice that of Mg(OH)2.

Hope this helps!

8 0

3 years ago

Read 2 more answers