3 years ago

Pls help will give brainiest

Chemistry

2 answers:

kozerog [31]3 years ago

4 0

Answer: A

Explanation:

olya-2409 [2.1K]3 years ago

3 0

The answer is A pretty sure

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Answer: Equilibrium constant for this reaction is $2.8 \times 10^{15}$ .

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Chemical reaction equation for the formation of nickel cyanide complex is as follows.

$Ni(OH)_{2}(s) + 4CN^{-}(aq) \rightleftharpoons [Ni(CN)_{4}^{2-}](aq) + 2OH^{-}(aq)$

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= $2.8 \times 10^{15}$

Thus, we can conclude that equilibrium constant for this reaction is $2.8 \times 10^{15}$ .

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