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jasenka [17]
3 years ago
15

Pls help will give brainiest

Chemistry
2 answers:
kozerog [31]3 years ago
4 0

Answer: A

Explanation:

olya-2409 [2.1K]3 years ago
3 0
The answer is A pretty sure
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B. if 6.73 g of na2co3 is dissolved in enough water to make 250. ml of solution, what is the molar concentration of sodium carbo
BARSIC [14]

Answer:- [Na_2CO_3]=0.254M , [Na^+]=0.508 M , [CO_3^2^-]=0.254M

Solution:- We are asked to calculate the molarity of sodium carbonate solution as well as the sodium and carbonate ions.

Molarity is moles of solute per liter of solution. We have been given with 6.73 grams of sodium carbonate and the volume of solution is 250.mL.  Grams are converted to moles and mL are converted to L and finally the moles are divided by liters to get the molarity of sodium carbonate.

Molar mass of sodium carbonate is 105.99 gram per mol. The calculations for the molarity of sodium carbonate are shown below:

\frac{6.73gNa_2CO_3}{250.mL}(\frac{1mol}{105.99g})(\frac{1000mL}{1L})

= 0.254MNa_2CO_3

So, molarity of sodium carbonate solution is 0.254 M.

sodium carbonate dissociate to give the ions as:

Na_2CO_3(aq)\rightarrow 2Na^+(aq)+CO_3^2^-

There is 1:2 mol ratio between sodium carbonate and sodium ion. So, the molarity of sodium ion will be two times of sodium carbonate molarity.

[Na^+]=2(0.254M) = 0.508 M

There is 1:1 mol ratio between sodium carbonate and carbonate ion. So, the molarity of carbonate ion will be equal to the molarity of sodium carbonate.

[CO_3^2^-]=0.254M


5 0
4 years ago
Which of the following is most likely to be covalent?<br> MgO <br> CO <br> CaO <br> BaO
Kisachek [45]

Answer:

CaO

Explanation:

CaO is the only compound that is a non-metal and a non-metal. The rest of the compounds are ionic, or metal and non-metal.

8 0
3 years ago
A compound is composed of 85.6% Carbon and the rest is Hydrogen. The molecular mass of the compound is 42.078g/mol. What is the
s344n2d4d5 [400]

The molecular formula for the compound is  C_{3} H_{6}

<u>Explanation</u>:

As with all of these problems, we assume 100 g of an unknown compound.

And thus, we determine the elemental composition by the given percentages.

Moles of carbon = 85.64 / 12.011

                            = 7.13 mol.

Moles of hydrogen = 14.36 / 1.00794

                               = 14.25 mol.

There are 2 moles of hydrogen per mole of carbon. And thus the empirical formula is CH_{2}.

And molecular formula = n × (empirical formula)

Thus, 42.08 = n × (12.011 + 2 × 1.00794)

And thus n = 3, and molecular formula = C_{3} H_{6}

3 0
3 years ago
How much heat is necessary to raise the temperature of a 15.0 g metal from 15.0 C to 25.0 C if the specific heat of that metal i
Bumek [7]

The solution would be like this for this specific problem:

<span><span>
E</span>=</span><span>mc</span>ΔT<span> <span>
= (</span>15<span> g</span><span>)(</span>1.91<span> <span>J<span><span>g∘</span>C</span></span>)(</span>25<span><span> ∘</span>C</span>−15<span><span> ∘</span>C</span><span>)
</span></span>= 28.65 * 10
= 286.5

<span>

I hope this helps and if you have any further questions, please don’t hesitate to ask again. </span>

5 0
3 years ago
In a particular electroplating process, the metal being plated has a +4 charge. If 861.8 C of charge pass through the cell, how
Xelga [282]

Answer: 2.2326\times 10^{-3} moles

Explanation:

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains 6.022\times 10^{23} number of particles.

We know that:

Charge on 1 electron = 1.6\times 10^{-19}C

Charge on 1 mole of electrons = 1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C

The metal being plated has a +4 charge, thus the equation will be:

M^{4+}+4e^-\rightarrow M

4\times 96500C of electricity deposits = 1 mole of metal

Thus 861.8 C of electricity deposits =\frac{1}{4\times 96500}\times 861.8=2.2326\times 10^{-3} moles of metal

Thus 2.2326\times 10^{-3} moles of metal should be plated

3 0
3 years ago
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