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yawa3891 [41]

3 years ago

ss="latex-formula">

Mathematics

1 answer:

Georgia [21]3 years ago

5 0

Answer:

answer=cos2 I ---------1

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Can you help with this please and also explain?

stira [4]

Answer:

avocado=4

Step-by-step explanation:

Hi there!

We are given the following equations:

snail + snail - cellphone=avocado

maple leaf * cellphone=10

0+maple leaf=5

snail = cellphone + 1

avocado=?

This may seem confusing at first, but let's try to find the value of one of the items to help us to solve for the others

For example, we have the equation 0 + maple leaf= 5

Which means if we subtract 0 from both sides, we should get the value of the maple leaf

Which means that the maple leaf= 5

Now we know that maple leaf * cellphone = 10

So that means 5*cellphone=10

Divide by 5 on both sides

cellphone= 2

We know that snail = cellphone + 1

As we learned from above, cellphone= 2

Which means that snail = 2+1=3

We know that snail + snail - cellphone = avocado

And as calculated from above, snail = 3 and cellphone = 2

Which means:

3 + 3 - 2= avocado

Add

6-2=avocado

Subtract

4=avocado

Hope this helps!

5 0

3 years ago

The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1

Aleksandr-060686 [28]

Answer:

a) The probability that a student has either a Visa card or a MasterCard is 0.71.

b) V and M are not independent.

Step-by-step explanation:

Given : The probability that a student has a Visa card (event V) is 0.63. The probability that a student has a MasterCard (event M) is 0.11. The probability that a student has both cards is 0.03.

To find :

a) The probability that a student has either a Visa card or a MasterCard ?

b) In this problem, are V and M independent ?

Solution :

The probability that a student has a visa card(event V) is P(V)= 0.63

The probability that a student has a MasterCard (event M) is P(M)= 0.11

The probability that a student has both cards is $P(V \cap M)=0.03$

a) Probability that a student has either a Visa card or a Master Card is given by,

$P(V \cup M) = P(V) + P(M) - P(V\cap M)$

$P(V \cup M) = 0.63+ 0.11- 0.03$

$P(V \cup M) =0.74- 0.03$

$P(V \cup M) =0.71$

The probability that a student has either a Visa card or a MasterCard is 0.71.

b) Two events, A and B, are independent if $P(A\cap B)=P(A)P(B)$

For V and M to be independent the condition is satisfied,

$P(V\cap M)=P(V)P(M)$

Substitute the values,

$0.03=0.63\times 0.11$

$0.03\neq 0.0693$

So, V and M are not independent.

6 0

3 years ago

If the radius of the circle above is 2 in, what is the area of the circle? A. 8 sq in B. 4 sq in C. 2 sq in D. 16 sq in

polet [3.4K]

Answer:

Step-by-step explanation:

6 0

3 years ago

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Help me please i will help you too

rosijanka [135]

Day 3 is A because it tell how many pieces of candies eaten in a minute.
Day 4 is 10 and 15 because the ratios go in a pattern by 5
Day 5 is D but I really dont know that one

4 0

3 years ago

IF THIS QUESTION IS EASY MAKE ME BRILLIST WHAT IS 10 X 6 ?

Dmitriy789 [7]

Answer:

its 60

Step-by-step explanation:

please mark brainliest

6 0

3 years ago

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