Answer:
a 4
Step-by-step explanation:
4x5=15jddjshshhshsjsjsjsjsjejejsjejejeejjssjsj
y - 3
g(y) = ------------------
y^2 - 3y + 9
To find the c. v., we must differentiate this function g(y) and set the derivative equal to zero:
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3)
g '(y) = --------------------------------------------
(y^2 - 3y + 9)^2
Note carefully: The denom. has no real roots, so division by zero is not going to be an issue here.
Simplifying the denominator of the derivative,
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3) => y^2 - 3y + 9 - [2y^2 - 3y - 6y + 9], or
-y^2 + 6y
Setting this result = to 0 produces the equation y(-y + 6) = 0, so
y = 0 and y = 6. These are your critical values. You may or may not have max or min at one or the other.
I believe the answer is range
Answer:
Because θ lies in quadrant II, 2θ must lie in quadrant IV. This means the tangent of 2θ is negative.
The adjacent side to θ is 7 because √(25²-24²)=7, so tanθ=7/24.
The double angle formula for tangent is tan 2θ = (2 tan θ) / (1 − tan² θ).
Substituting the value for tanθ in and keeping in mind that this is in quadrant IV, we get tan 2θ = -(2(7/24)/(1-(7/24)²)).
Simplified, this becomes tan 2θ = -336/527.
Therefore, the answer is C. -336/527.
Answer:
x = 
Step-by-step explanation:
Given
= 
( cross- multiply )
25 × 2x = 5 × 4
50x = 20 ( divide both sides by 50 )
x = 
=
