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3 years ago

Which ordered pair is a solution to the equation 3x+2y=6 ?

2 answers:

8 0

You need to use all of them until you find the answer so lets fo this!
a. (-10,-12) x=-10 y=-12
3x+2y=6
3*(-10)+2*(-12)=6
-30-24=6
-54=6
This is incorrect,now we try the othe options
b.(10,12) x=10 y=12
3x+2y=6
3*10+2*12=6
30+24=6
54=6
This is incorrect then we try the other option
c. (-10,12) x=-10 y=12
3x+2y=6
3*(-10)+2*12=6
-30+24=6
6=6
And this is the correct answer. So the answer is c. (-10,12)

stepladder [879]3 years ago

7 0

3(-10)+2(-12)=-54 That's not right!

3(10)+2(12)=54 That's also not right

3(-10)+2(12)=-6 Close but not right

3(10)+2(-12)=6 is the correct answer

Your welcome love u

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Hi!

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To do that, we subtract
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The probability of a train arriving on time and leaving on time is 0.8. The probability that the train arrives on time and leave

kkurt [141]

Answer:

0.9524

Step-by-step explanation:

Note enough information is given in this problem. I will do a similar problem like this. The problem is:

The Probability of a train arriving on time and leaving on time is 0.8.The probability of the same train arriving on time is 0.84. The probability of the same train leaving on time is 0.86.Given the train arrived on time, what is the probability it will leave on time?

Solution:

This is conditional probability.

Given:

Probability train arrive on time and leave on time = 0.8
Probability train arrive on time = 0.84
Probability train leave on time = 0.86

Now, according to conditional probability formula, we can write:

$P(Leave \ on \ time | arrive \ on \ time)$ = P(arrive ∩ leave) / P(arrive)

Arrive ∩ leave means probability of arriving AND leaving on time, that is given as "0.8"

and

P(arrive) means probability arriving on time given as 0.84, so:

0.8/0.84 = 0.9524

This is the answer.

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