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Mademuasel [1]
3 years ago
15

A small cube with side length 6y is placed inside a larger cube with side length 4x^2. What is the difference in the volume of t

he cubes?
Mathematics
2 answers:
sleet_krkn [62]3 years ago
6 0

Answer:

(64x^{6}-216y^{3})\ units^{3}

Step-by-step explanation:

we know that

The volume of a cube is equal to

V=s^{3}

where

s is the length side of a cube

Step 1

Find the volume of the smaller cube

we have

s=6y\ units

substitute the value in the formula

V1=(6y)^{3}=216y^{3}\ units^{3}

Step 2

Find the volume of the larger cube

we have

s=4x^{2}\ units

substitute the value in the formula

V2=(4x^{2})^{3}=64x^{6}\ units^{3}

Step 3

Find the difference in the volume of the cubes

V2-V1=(64x^{6}-216y^{3})\ units^{3}


fomenos3 years ago
3 0

the different volume is the numbers. 4*2*6=?


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