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Mariana [72]
3 years ago
14

The speedometer needle in a car is 2.5 inches long. When accelerating from 0 to 60 miles per hour the needle

Mathematics
1 answer:
melamori03 [73]3 years ago
7 0

The arc length traveled by the needle is 7.0904in^{2}

Step-by-step explanation:

<u></u>

<u>Step 1</u>

In the above question  are given that

The speedometer needle in a car is 2.5 inches long

The needle  sweeps out an arc of 130°.

Let r be the length of the speedometer needle,So

r=2.5

m∠C=130°

<u>Step 2</u>

The formula for determining the area of the sector is

A=\frac{m}{360}*\pi r^{2}

Where,the central angle is m°

and The radius is r

Substituting the value of m and  r from the step 1  in the below equation we get

A=\frac{130}{360}*\pi *2.5^{2}

A= 0.3611*\pi*6.5=7.0904 in^{2}

Hence the value of the Area of the sector is = 7.0904 in^{2}

<u></u>

<u>Step 3</u>

<u>So, the arc length traveled by the needle </u><u> 7.0904 </u>in^{2}<u />

<u></u>

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3 years ago
Doug hits a baseball straight towards a 15 ft high fence that is 400 ft from home plate. The ball is hit 2.5ft above the ground
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Step-by-step explanation:

u = Initial velocity of baseball

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x=u_xt\\\Rightarrow x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{400}{u\cos30^{\circ}}\\\Rightarrow t=\dfrac{400}{u\dfrac{\sqrt{3}}{2}}\\\Rightarrow t=\dfrac{800}{u\sqrt{3}}

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y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow y=y_0+u\sin\theta t+\dfrac{1}{2}a_yt^2\\\Rightarrow 15=2.5+u\sin30^{\circ}(\dfrac{800}{u\sqrt{3}})+\dfrac{1}{2}\times -32.2\times (\dfrac{800}{u\sqrt{3}})^2\\\Rightarrow \dfrac{400}{\sqrt{3}}-\dfrac{10304000}{3u^2}-12.5=0\\\Rightarrow 218.44=\dfrac{10304000}{3u^2}\\\Rightarrow u=\sqrt{\dfrac{10304000}{3\times218.44}}\\\Rightarrow u=125.4\ \text{m/s}

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Step-by-step explanation:

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