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Mariana [72]
3 years ago
14

The speedometer needle in a car is 2.5 inches long. When accelerating from 0 to 60 miles per hour the needle

Mathematics
1 answer:
melamori03 [73]3 years ago
7 0

The arc length traveled by the needle is 7.0904in^{2}

Step-by-step explanation:

<u></u>

<u>Step 1</u>

In the above question  are given that

The speedometer needle in a car is 2.5 inches long

The needle  sweeps out an arc of 130°.

Let r be the length of the speedometer needle,So

r=2.5

m∠C=130°

<u>Step 2</u>

The formula for determining the area of the sector is

A=\frac{m}{360}*\pi r^{2}

Where,the central angle is m°

and The radius is r

Substituting the value of m and  r from the step 1  in the below equation we get

A=\frac{130}{360}*\pi *2.5^{2}

A= 0.3611*\pi*6.5=7.0904 in^{2}

Hence the value of the Area of the sector is = 7.0904 in^{2}

<u></u>

<u>Step 3</u>

<u>So, the arc length traveled by the needle </u><u> 7.0904 </u>in^{2}<u />

<u></u>

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\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

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\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}

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\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

If the diameter is equal to the side length of the square, then:
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Therefore:

\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

So the ratio of the area of the circle to the original square is:

\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

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The area of the shaded region is 8.1838. The area of the shaded region is calculated by subtracting the area of the triangle from the area of the sector of the circle.

<h3>How to calculate the area of the sector?</h3>

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