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sineoko [7]
3 years ago
7

Angie's family goes to the movies and got popcorn and drinks to enjoy during the show. The family got 5 drinks and 3 tubes of po

pcorn to share. They spent $32.50 on concessions. JASON FAMILY GOT 4 DRINKS AND 6 TUBES OF POPCORN TO SHARE. THEY SPENT $44.00. HOW MUCH DID EACH POPCORN COST AND HOW MUCH WHERE DRINKS?
Mathematics
1 answer:
AleksAgata [21]3 years ago
8 0

Answer:

Cost of each popcorn = $3.50

Cost of drinks = $31.50

Step-by-step explanation:

Let each drink's cost be represented by $d

Let each popcorn's cost be represented by $p

5 drinks = 5*d = $5d; 3 tubes of popcorn = 3*p = $3p

4 drinks = 4*d = $4d; 6 tubes of popcorn = 6*p = $6p

// Setting up the system of equations

5d + 3p = 32.50     ...(1)

4d + 6p = 44.00     ...(2)

Multiply equation 1 by 2

10d + 6p = 65.00   ...(3)

4d + 6p = 44.00     ...(2)

Subtract equation 2 from equation 3

10d - 4d + 6p - 6p = 65.00 - 44.00

6d = 21.00

Divide both sides by 6

\frac{6d}{6}-\frac{21.00}{6}\\  \\d = $3.50

Substitute d = 3.5 in equation 2

4*3.50 + 6p = 44.00

14.00 + 6p = 44.00

6p = 44.00 - 14.00

6p = 30.00

Divide both sides by 6

\frac{6p}{6} = \frac{30.00}{6}\\ \\p = 5.00

So, each popcorn costs $5.00

For the drinks. Angie's family got 5 drinks and Jason's family got 4 drinks. So, a total of 9 drinks.

Cost of drinks = $3.50 * 9 = $31.50

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3 years ago
I select two cards from a standard deck of 52 cards and observe the color of each (26 cards in the deck are red and 26 are black
lilavasa [31]

Answer:

B) S= {(red, red), (red, black), (black, red), (black, black)}

See explanation below.

Step-by-step explanation:

Previous concepts

The sample space of an experiment by definition "is the set of all possible outcomes or results of that experiment".

Solution to the problem

We know that we have 52 cards. 26 of them red and the other 26 black. And we are going to select two cards at random. We are interested on the correct sampling space. We analyze one by one the options given.

A) S= {red, black}

False. We can obtain two red cards for example or two black cards and these pairs are not included in the sample space provided.

B) S= {(red, red), (red, black), (black, red), (black, black)}, where, for example, (red, red) stands for the event "the first card is red and the second card is red."

True. The cardinality for the sample space is 2^2 = 4 possible outcomes. And as we can see here we have all the possible options included (red, red), (red, black), (black, red), (black, black). So then that's the correct option for the sampling space.

C) S= {(red, red), (red, black), (black, black)}, where, for example, (red, red) stands for the event "the first card is red and the second card is red."

False, the cardinality of the sample space is 2^2 = 4 and on this case the sample space provided have just 3 elements or possible outcomes. We don't have include the possibl option (black, red).

D) S= {0, 1, 2}.

False the sample space are related to red and black cards and we can't have numbers as the possible outcomes for the experiment.

E) All of the above.

False, option B is correct.  

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Serjik [45]

Answer:

I think b

Step-by-step explanation:

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Natasha2012 [34]

Answer:

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Step-by-step explanation:

They drive the way twice; once they go there and then they go home. Therefore, 870 times 2 equals 1740.

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There are 203 apples in a basket. How many children can share these apples equally? How many apples would each child get?
tangare [24]
I think this is factorials
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hope this helps
6 0
3 years ago
Read 2 more answers
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