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2 years ago

4x-y=3 is it linear or no

2 answers:

6 0

Answer:NO dodo its wrong you cant d o 1 side to toehr u gotta do left to right then side to side the denominatior!:)

Step-by-step explanation:

EASY

OLga [1]2 years ago

3 0

Answer:

Step-by-step explanation:

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What ratios are equivalent to 4:3

Brums [2.3K]

Answer:

here are a few that are equivalent

8:6

28:21

48:36

68:51

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2 years ago

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Simplify -9+5(y+3)-2y

JulijaS [17]

3y+6 is the answer

-9+5(y+3)-2y
-9+5y+15-2y
-9+3y+15
=3y+6

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3 years ago

What is the quotient?

Ugo [173]

Answer:

I got 4e+12 which is d

I think

Step-by-step explanation:

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2 years ago

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Ad libitum [116K]

Answer:

Step-by-step explanation:

The base of the larger triangle is <em>twice as large</em> as the smaller one: <em>6 v 3 --> 6 : 3 --></em> 2 : 1.

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2 years ago

Evaluate the following integral using trigonometric substitution.

wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ , using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as $asin \theta$ i.e $x = a sin\theta$ .

All integrals in the form $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ are always evaluated using the substitute given where 'a' is any constant.

From the given integral, $\int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx$ where a = 7 in this case.

The substitute will therefore be $x = 7 sin\theta$

2.) Given $x = 7 sin\theta$

$\frac{dx}{d \theta} = 7cos \theta$

cross multiplying

$dx = 7cos\theta d\theta$

3.) Rewriting the given integral using the substiution will result into;

$\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)} } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)} }}} \, 7cos\theta d\theta\\$

$= \int\limits343 cos^{2} \theta \, d\theta$

8 0

3 years ago