Question

Please help me do this maths calculation ​

Answer 1

Answer:

x = $y^{2}$ - 4y + 12

Step-by-step explanation:

y = 2 + $\sqrt{x-8}$

Put the 2 on the other side

y - 2 = $\sqrt{x-8}$

Square both sides

$(y-2)^{2}$ = x - 8

Expand the brackets

$y^{2}$ - 4y + 4 = x-8

Move 8 to the other side

x = $y^{2}$ - 4y + 12

Answer 2

Answer:

x=y^2-4y+12 is the required answer