Answer:
180 meters
Explanation:
Josh walks 6 meters to the right and the 6 meters back. This means that in one time, Josh walks a total distance of 6+6 = 12 meters
Now, we are given that Josh walks this same distance 15 times.
Therefore, we will multiply this distance by 15 to get the total distance that he walks as follows:
Total distance = 12*15 = 180 meters
Based on the above calculations, Josh walks 180 meters over the course of the class
Hope this helps :)
Answer:
<em>The table is 2.08 m high</em>
Explanation:
<u>Horizontal Motion</u>
When an object is thrown horizontally with a speed vo from a height h, the range or maximum horizontal distance traveled by the object can be calculated as follows:

If we know the range d = 0.15 m and the speed v = 0.23 m/s, we can solve the above equation for h:



The table is 2.08 m high
Average speed =
(total distance covered)
divided by
(total time spent covering the distance)
here tension in the string is counter balanced by weight of block of mass m1
so we can say


now on the other side the block which is placed on the inclined plane
we can say that component of weight of the block and friction force is counter balanced by tension force

now we can plug in all values to find the friction force


so it will have 0.83 N force on it due to friction
now to find the friction coefficient

here we know that


now from above equation


so friction coefficient will be 0.38