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3 years ago

If a magnet repels a metal object what can you say about the pole of the magnet and the pole of the object?

Physics

2 answers:

sleet_krkn [62]3 years ago

7 0

Poles are the same D is the right answer

Ilya [14]3 years ago

3 0

Answer:

The correct answer is option D. The poles are the same.

Explanation:

Hello!

Let's solve this!

For an object to be attracted to a magnet, the charges must be opposite. But when, otherwise, they repel, it means that the charges (the poles) are the same.

In this case we conclude that the correct answer is option D. The poles are the same.

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A ball of silly putty hits andsticks to a bowling ball that was initially at rest. After thecollision, the total kinetic energy

Jobisdone [24]

Answer:

3. less than the kinetic energy of thesilly putty before the collision.

Explanation:

This is because kinetic energy is dependent on the mass and velocity of an object. Mathematically, it is given as:

K. E. = ½*m*v²

Where m = mass

v = velocity

In the case of the silly putty, we know that the masses of the ball of silly putty and the bowling ball are conserved, hence, the kinetic energy depends solely on the velocity at which the object moves.

After the collision with the bowling ball, because of how heavy a bowling ball is, the speed of the silly putty and bowling ball will definitely be less than the speed of the silly putty before collision, i. e. u > v.

Hence, the kinetic energy after collision will be less than the kinetic energy before collision.

7 0

3 years ago

Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a s

Alenkasestr [34]

Answer: 1.289 m

Explanation:

The path the cobra's venom follows since it is spitted until it hits the ground, is described by a parabola. Hence, the equations for parabolic motion (which has two components) can be applied to solve this problem:

<u>x-component: </u>

$x=V_{o}cos\theta t$ (1)

Where:

$x$ is the horizontal distance traveled by the venom

$V_{o}=3.10 m/s$ is the venom's initial speed

$\theta=47\°$ is the angle

$t$ is the time since the venom is spitted until it hits the ground

<u>y-component: </u>

$y=y_{o}+V_{o}sin\theta t+\frac{gt^{2}}{2}$ (2)

Where:

$y_{o}=0.44 m$ is the initial height of the venom

$y=0$ is the final height of the venom (when it finally hits the ground)

$g=-9.8m/s^{2}$ is the acceleration due gravity

Let's begin with (2) to find the time it takes the complete path:

$0=0.44 m+3.10 m/s sin\theta(47\°)+\frac{-9.8m/s^{2} t^{2}}{2}$ (3)

Rewritting (3):

$-4.9 m/s^{2} t^{2} + 2.267 m/s t + 0.44 m=0$ (4)

This is a quadratic equation (also called equation of the second degree) of the form $at^{2}+bt+c=0$ , which can be solved with the following formula: