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2 years ago

Distinguish the difference in mass and weight

1 answer:

3 0

Ok to distinguish the difference you just find out why there's science lol.......anyways.....Mass is the amount of space being taken up in a certain place (or possibly all the world) and weight is the heaviness of an person or thing kk??? also if my answer was best, plzz give brainliest (trust me i need it) Have a great day and Christmas (if u celebrate it)!!

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If this were a theoretical frictionless plane, what would be the mechanical advantage?

alex41 [277]

Mechanical advantage (MA = slope/height)
here length of slope = 9Hheight = H so mechanical advantage = ---- 9H/H= 9

3 0

2 years ago

What is the wavelength of a wave?

Sunny_sXe [5.5K]

The wavelength is the spatial period of a periodic wave—the distance over which the wave's shape repeats.

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2 years ago

A 1200-kg ore cart is rolling at 10.8 m/s across a flat friction-free surface. a crane suddenly drops of ore vertically into the

Andre45 [30]

The value of the final speed depends on the mass of the ore.

Let's call m the mass of the ore. We can solve the exercise by requiring the conservation of momentum, which must be the same before and after the ore is loaded.

Initially, there is only the cart, so the momentum is
$p=Mv=(1200 kg)(10.8 m/s)=12960 kg m/s$
After the ore is loaded, the new mass will be (1200 kg+m), and the new speed is $v_f$ . The momentum p is conserved, so it is still 12960 kg m/s. Therefore, we have
$p=12960 kg m/s =(1200 kg+m)v_f$
and so the final speed is
$v_f = \frac{12960 kg m/s}{1200 kg +m}$

5 0

3 years ago

A 160 g basketball has a 32.7 cm diameter and may be approximated as a thin spherical shell. Starting from rest, how long will i

mafiozo [28]

Answer:

t = 0.24 s

Explanation:

As seen in the attached diagram, we are going to use dynamics to resolve the problem, so we will be using the equations for the translation and the rotation dyamics:

Translation: ΣF = ma

Rotation: ΣM = Iα ; where α = angular acceleration

Because the angular acceleration is equal to the linear acceleration divided by the radius, the rotation equation also can be represented like:

ΣM = I(a/R)

Now we are going to resolve and combine these equations.

For translation: Fx - Ffr = ma

We know that Fx = mgSin27°, so we substitute:

(1) mgSin27° - Ffr = ma

For rotation: (Ffr)(R) = (2/3mR²)(a/R)

The radius cancel each other:

(2) Ffr = 2/3 ma

We substitute equation (2) in equation (1):

mgSin27° - 2/3 ma = ma

mgSin27° = ma + 2/3 ma

The mass gets cancelled:

gSin27° = 5/3 a

a = (3/5)(gSin27°)

a = (3/5)(9.8 m/s²(Sin27°))

a = 2.67 m/s²

If we assume that the acceleration is a constant we can use the next equation to find the velocity:

V = √2ad; where d = 0.327m

V = √2(2.67 m/s²)(0.327m)

V = 1.32 m/s

Because V = d/t

t = d/V

t = 0.327m/1.32 m/s

t = 0.24 s

7 0

3 years ago

Complete the paragraph to describe the relationship between kinetic energy and braking distance. Use . A car moves at a speed of

Mariana [72]

ke prop to v^2

ke1/v1^2=ke2/v2^2

400/50x50=joules/100x100

400x2x2

1600j

7 0

3 years ago

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