Answer:
51.85m/s
Explanation:
Given parameters:
Mass of ball = 0.0459kg
Force = 2380N
Time taken = 0.001s
Unknown:
Speed of the ball afterwards = ?
Solution:
To solve this problem, we use Newton's second law of motion:
F = m x
F is the force
m is the mass
v is the final velocity
u is the initial velocity
t is the time taken
2380 = 0.0459 x
0.0459v = 2.38
v = 51.85m/s
Hello!
Use the equation for momentum:
Plug in the given mass and velocity into the equation:
Explanation:
Newton's 2nd Law can be expressed in terms of the object's momentum, in this case the expelled exhaust gases, as
(1)
Assuming that the velocity remains constant then
Solving for we get
Before we plug in the given values, we need to convert them first to their appropriate units:
The thrust <em>F</em><em> </em> is
The exhaust rate dm/dt is
Therefore, the velocity at which the exhaust gases exit the engines is
Answer:
d= 100m
Explanation:
Cheetah kinematic
The cheetah moves with uniformly accelerated movement, and the formulas that describe this movement are:
d= v₀*t + (1/2)*a*t² Formula (1)
vf²=v₀²+2*a*d Formula (2)
vf=v₀+a*t Formula (3)
Where:
d:distance in meters (m)
v₀: initial speed in m/s
vf: final speed in m/s
a: acceleration in m/s²
t: time in seconds (s)
Known Data
v₀ =0
a = 4.5 m/s²
vf= 30 m/s.
Problem development
We apply the formula (2) that has known data to calculate the distance :
vf²=v₀²+2*a*d
(30)²= 0 + 2* 4.5* d
d= 100m